<span>A perpendicular bisector of a line segment is a line segment perpendicular to and passing through the midpoint of (left figure). The perpendicular bisector
of a line segment can be constructed using a compass by drawing circles
centered at and with radius and connecting their two intersections.
Hope i helped
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X^2 + 4x -21
= (x +7)(x - 3)
hope that helps
Answer:
![f^{-1}(x)=\sqrt[3]{x}-1](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D-1)
Step-by-step explanation:
![f(x)=(x+1)^3\\\\y=(x+1)^3\\\\x=(y+1)^3\\\\\sqrt[3]{x}=y+1\\\\y=\sqrt[3]{x}-1\\ \\f^{-1}(x)=\sqrt[3]{x}-1](https://tex.z-dn.net/?f=f%28x%29%3D%28x%2B1%29%5E3%5C%5C%5C%5Cy%3D%28x%2B1%29%5E3%5C%5C%5C%5Cx%3D%28y%2B1%29%5E3%5C%5C%5C%5C%5Csqrt%5B3%5D%7Bx%7D%3Dy%2B1%5C%5C%5C%5Cy%3D%5Csqrt%5B3%5D%7Bx%7D-1%5C%5C%20%5C%5Cf%5E%7B-1%7D%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D-1)
Graphing both inverses, they will be symmetrical about the line 
.
Answer:
1 solution
Step-by-step explanation:
It could be a linear graph with a negative slope
x axis is height above ground and y axis id air pressure
so there willbe a point at (0,14.7) on y axis representing the pressure at sea level. There will be another point at (3.6, 7.35) where air pressure is half that at ground level. The straight line will continue until it reaches the x axis ad (0, 7.2) where there is no air pressure.
