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2 years ago

6

Hi Guyss Can you pls help?

1 answer:

pogonyaev2 years ago

5 0

B!

the golden ratio is where the long side can be split into two pieces and both can still be longer than the short side of the rectangle

A. 34x2=68 which is higher than 55 so it couldn’t split into two bigger halves
B. 20x2=40 which is smaller than 45 so it could split into two bigger halves (this one does fit the golden ratio btw)
C. 18x2=36 which is bigger than 34 and couldn’t split into two larger halves

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3 0

3 years ago

Help ASAP show work please thanksss!!!!

Llana [10]

Answer:

$\displaystyle log_\frac{1}{2}(64)=-6$

Step-by-step explanation:

<u>Properties of Logarithms</u>

We'll recall below the basic properties of logarithms:

$log_b(1) = 0$

Logarithm of the base:

$log_b(b) = 1$

Product rule:

$log_b(xy) = log_b(x) + log_b(y)$

Division rule:

$\displaystyle log_b(\frac{x}{y}) = log_b(x) - log_b(y)$

Power rule:

$log_b(x^n) = n\cdot log_b(x)$

Change of base:

$\displaystyle log_b(x) = \frac{ log_a(x)}{log_a(b)}$

Simplifying logarithms often requires the application of one or more of the above properties.

Simplify

$\displaystyle log_\frac{1}{2}(64)$

Factoring $64=2^6$ .

$\displaystyle log_\frac{1}{2}(64)=\displaystyle log_\frac{1}{2}(2^6)$

Applying the power rule:

$\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}(2)$

Since

$\displaystyle 2=(1/2)^{-1}$

$\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}((1/2)^{-1})$

Applying the power rule:

$\displaystyle log_\frac{1}{2}(64)=-6\cdot log_\frac{1}{2}(\frac{1}{2})$

Applying the logarithm of the base:

$\mathbf{\displaystyle log_\frac{1}{2}(64)=-6}$

5 0

2 years ago

Solve:<br> n = 8<br> 4<br> O n = 2<br> 0 n = 12<br> Ô n = 24<br> 0 n = 32

zzz [600]

Answer:

1/4 n = 8

n = 8 * 4

n = 32

so option 4 i.e.

n = 32. is the ans

7 0

2 years ago

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Usimov [2.4K]

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5 0

3 years ago

What is the simplest form of this expression?

Dimas [21]

Answer:

(4-m-1)-5

Remove the bracket

= 4-m-1-5

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Hope this helps.

7 0

3 years ago