Answer:
The distance from A to B is 736.2 to the nearest tenth foot
Step-by-step explanation:
In ΔCAB
∵ m∠CAD = 30° ⇒ exterior angle of Δ at vertex A
∴ m∠CAD = m∠ACB + m∠ABC
∵ m∠ABC = 20°
∴ m∠ACB = 30° - 20° = 10°
We will use the sin rule to find the distance AB
∵ 
∴
≅ 736.2 to the nearest tenth foot
To get your answer, you will need to find the perpendicular slope for -1/3x which is just the opposite therefore it will be 3x. Your slope is 3x as perpendicular so use this slope to do point slope. Y-1=3(x-2). Distribute y-1=3x-6. Add 1 to both sides. (-1+1) (-6+1)=-5. So your equation in slope intercept form is y=3x-5. Going through the two points.
Hope this helps!
Centralangle/360 times area of circle=sector area
120/360 times pi8²=
(1/3)(64pi)=64pi/3 square inches
Answer:
The maximum height is 46.64 feet.
Step-by-step explanation:
If we take the derivative of h whit respect to t and equal this to zero we would find the value of t which corresponds to the maximum h.
So, we have the function h(t):

Taking the derivative, we have:

Now, we solve it for t:

Finally, we put this value of t into the original equation.

Therefore, the maximum height is 46.64 feet. All the given options are wrong, the one that comes closest is option A.
I hope it helps you!
Answer:
Step-by-step explanation:
Give the rate of change of sales revenue of a store modeled by the equation
. The Total sales revenue function S(t) can be gotten by integrating the function given as shown;

a) The total sales for the first week after the campaign ends (t = 0 to t = 7) is expressed as shown;


Total sales = S(7) - S(0)
= 6,860 - 0
Total sales for the first week = $6,860
b) The total sales for the secondweek after the campaign ends (t = 7 to t = 14) is expressed as shown;
Total sales for the second week = S(14)-S(7)
Given S(7) = 6,860
To get S(14);

The total sales for the second week after campaign ends = 13,720 - 6,860
= $6,860