Answer:
The common oxide of nitrogen that has a positive ΔS°f is nitric oxide (NO)
Explanation:
Without reference to thermodynamic data, we have;
1) N₂ (g) + O₂ (g) ⇄ 2 NO (g)
1 unit of N₂ + 1 unit of O₂ (total of 2 units) gives 2 units of NO, (Increase of +0 disorder)
∴ΔS°f = +ve
2) 2NO + O₂ → 2NO₂
2 unit of NO + 1 unit of O₂ (total of 3 units) gives 2 units of NO₂, (Decrease of disorder)
∴ΔS°f = -ve
3) N₂ + 1/2 O₂ → N₂O
1 unit of N₂ + 1/2 unit of O₂ (total of 1+1/2 units) gives 2 units of NO₂, (Decrease of disorder)
∴ΔS°f = -ve
4) 4 NO₂ + O₂ → 2N₂O₅
4 unit of NO₂ + 1 unit of O₂ (total of 5 units) gives 2 units of N₂O₅, (Decrease of disorder)
∴ΔS°f = -ve
5) NO + NO₂ ⇄ N₂O₃
1 unit of NO + 1 unit of NO₂ (total of 2 units) gives 1 unit of N₂O₃, (Decrease of disorder)
∴ΔS°f = -ve
Therefore, the common oxide of nitrogen that has a positive ΔS°f without reference to thermodynamic data is nitric oxide NO.
Answer:
the Molecular formula will be; C10H14O
Explanation:
Given the data in the question;
Chrysanthenone is an unsaturated ketone,
it has M+ = 150 and contains 2 double bond(s) and 2 ring(s).
molecular formula = ?
we know that ketone contain 1 oxygen and mass of oxygen is 16
so mass of the C and H remaining will be;
⇒ 150 - 16 = 134
Now we determine the number of C atoms;
⇒ 134 / 13 = 10
hydrocarbon with 10 hydrogen atom have CnH2n+2 means
⇒ ( 10 × 2 ) +2 = 22 hydrogens
But then we have 3 unsaturation meaning 6 hydrogens less and also we have ring meaning 2 more hydrogens
⇒ 22 - 6 - 2 = 14
Hence the Molecular formula will be; C10H14O
Answer:
Explanation:
Electrons are the negatively charged particles of an atom that are involved in chemical reactions. They are located outside the nucleus of an atom
Answer : The balanced redox reaction will be,
Explanation :
The given chemical equation is,
In the half reaction method, the number of atoms in each half reaction and number of electrons must be balanced.
The half reactions in the acidic medium are :
Reduction : 
......(1)
Oxidation : 
.......(2)
Now multiply the equation (2) by 4 and then added both equation, we get the balanced redox reaction.
Thus, the balanced redox reaction will be,
<span> 2KCl(s) => 2K(s) + Cl2(g) </span>is correctly balanced. Becuase <span>2 K, 2 Cl on the left, and 2 K, 2 Cl on the right.</span>
