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grandymaker [24]

3 years ago

10

Urgent!

1 answer:

Doss [256]3 years ago

7 0

Answer:

${(1 - 2x)}^{p} = 1 + ( - 2x)p + \frac{1}{2!} p(p - 1) {( - 2x)}^{2} + ... \\ \frac{4}{2!} p(p - 1) = 40 \\ p(p - 1) = 20 \\ {p}^{2} - p = 20 \\ {p}^{2} - p - 20 = 0\\ ( p - 5)(p + 4) = 0\\ p = 5 \: or \: p = - 4 \\ \because \: p > 0 \\ \therefore \: p = 5$ Apply the binomial expansion...

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16*7/8 in fraction form

arlik [135]

Answer:

<h2>135/8</h2>

Step-by-step explanation:

16 x 8 + 7 = 135

Put that number over 8.

135/8

<em>Hope this helps</em>

5 0

3 years ago

What is the standard form of 5x^2+5y^2-10x+20y-30=0

o-na [289]

$5x^2+5y^2-10x+20y-30=0$

We need to get the equation in square form

We apply completing the square method

$5x^2-10x+5y^2+20y-30=0$

Divide all the terms by 5

$x^2-2x+y^2+4y-6=0$

Group x terms and y terms separately

$(x^2-2x)+(y^2+4y)-6=0$

By completing the square method, we take half of coefficient of x and square it

$\frac{-2}{2} = -1$

square it $(-1)^2= 1$

Add 1 on both sides

$(x^2-2x+1)+(y^2+4y)-6=+1$

$\frac{4}{2} = 2$

square it $(2)^2= 4$

Add 4 on both sides

$(x^2-2x+1)+(y^2+4y+4)-6=0+1+4$

Add 6 on both sides

$(x^2-2x+1)+(y^2+4y+4)=6+1+4$

Now factor both parenthesis

$(x-1)^2+(y+2)^2=11$

The equation of the circle is $(x-1)^2+(y+2)^2=11$

7 0

4 years ago

How many times can 80 go into 103

Black_prince [1.1K]

1 with a remainder of 23

7 0

4 years ago

Read 2 more answers

What is the value of x?<br> Enter your answer in the box.<br> X=

krek1111 [17]

Answer:

x=11 just a guess not so sure

7 0

3 years ago

What is the sum of 5/11 + 1/3 in lowest terms?

trapecia [35]

Answer:

5/11+1/3

= <u>5*3 + 1*11</u>

33

= <u>15+11</u>

33

= 26/33

Can you thanks me?

3 0

2 years ago