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4 years ago

How many triangles can be constructed with three angles, each measuring 64°?

Mathematics

1 answer:

juin [17]4 years ago

7 0

C. None because the sum of the angles in a triangle is 180 degrees

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Richard works 5 days a week and 8 hours a day his daily wage is 184 dollars. find his (a) hourly wage rate (b) weekly wage rate

GrogVix [38]

He would Earn 920 Dollars per week.
184 x 5 = 920 ^^^

His hourly wage is 23 Dollars an hour.
184 divided by 8 = 23 ^^^
A = 23$
B = 920$

7 0

4 years ago

Find, correct to four decimal places, the length of the curve of intersection of the cylinder 16x2 + y2 = 16 and the plane x + y

lubasha [3.4K]

First find a parameterization for the curve of intersection.

Given the equation of a cylinder, a natural choice for a parameterization would be one utilizing cylindrical coordinates. Here,

$16x^2+y^2=16\implies x^2+\left(\dfrac y4\right)^2=1$

which suggests we could use

$\begin{cases}x(t)=\cos t\\y(t)=4\sin t\\z(t)\end{cases}$

with $0\le t\le2\pi$ , and we get $z(t)$ from the equation of the plane,

$x+y+z=12\implies z(t)=12-x(t)-y(t)=12-\cos t-4\sin t$

Now use the arc length formula:

$\displaystyle\ell=\int_0^{2\pi}\sqrt{\left(\dfrac{\mathrm dx}{\mathrm dt}\right)^2+\left(\dfrac{\mathrm dy}{\mathrm dt}\right)^2+\left(\dfrac{\mathrm dz}{\mathrm dt}\right)^2}\,\mathrm dt$

$\displaystyle\ell=\int_0^{2\pi}\sqrt{\sin^2t+16\cos^2t+(\sin t-4\cos t)^2}\,\mathrm dt$

$\displaystyle\ell=\sqrt2\int_0^{2\pi}\sqrt{\sin^2t-4\cos t\sin t+16\cos^2t}\,\mathrm dt\approx\boxed{24.0878}$

4 0

4 years ago

Please help me with this question

Vikki [24]

Answer:

see below

Step-by-step explanation:

The third table shows a relationship of y=2x.

_____

Essentially, you have to see whether the value of y/x is constant for all the values in a table. If it is not, then the relation is not proportional.

in the first table, -4/-2 ≠ -3/-1

in the second table, -4/-2 ≠ 3/1

in the fourth table, -4/-2 ≠ 6/2

5 0

3 years ago

Can someone tell me which ones in first place and which ones in last place?

skad [1K]

Pretty sure purple would be the first and green would be the last

7 0

3 years ago

The amounts of time employees of a telecommunications company have worked for the company are normally distributed with a mean o

Fynjy0 [20]

Answer:

a) 5.6 years

b) 0.4478

Step-by-step explanation:

We are given the following in the question:

Mean, μ = 5.6 years

Standard Deviation, σ = 1.9 years

Sample size, n = 18

We are given that the distribution of amounts of time is a bell shaped distribution that is a normal distribution.

a) Mean of each sample.

The best estimator of the sample mean is the population mean itself. Thus, we have:

$\mu_{x} = \mu = 5.6$

Thus, the sample mean is 5.6 years.

b) Standard error

Formula:

$S.E = \dfrac{\sigma}{\sqrt{n}}$

Putting values, we have.

$S.E = \dfrac{1.9}{\sqrt{18}} = 0.4478$

Thus, the standard error is 0.4478.

7 0

3 years ago