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3 years ago

(-8, -6) is reflected across the y -axis what is the new coordniated?

1 answer:

4 0

When reflecting across the y-axis, the y coordinate stays the same.
(x, y) —> (-x, y)
Since the x-coordinate is already a negative we change it to a positive
(-8, -6) —> (8, -6)

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Answer:

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3 years ago

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What is the greatest common factor of 44c^5, 22c^3 and 11c^4

Alexxandr [17]

$\text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3$

Solution:

Given that, we have to find the greatest common factor of $44c^5, 22c^3 , 11c^4$

The greatest number that is a factor of two (or more) other numbers.

When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor

$\underline{\text{ GCF of } 44c^5, 22c^3 , 11c^4 :}$

First find the GCF of numbers and then find the GCF of variables and then multiply them together

Step 1: GCF of 44, 22 and 11

The factors of 11 are: 1, 11

The factors of 22 are: 1, 2, 11, 22

The factors of 44 are: 1, 2, 4, 11, 22, 44

11 is the greatest factor that is common in above three list

Then the greatest common factor is 11

$\text{ Step 2: GCF of }c^5, c^3 , c^4$

$c^5 = c^3 \times c^2\\\\c^3 = c^2 \times c^1 \text{ or } c^3\\\\c^4 = c^3 \times c^1$

Thus the greatest common factor is $c^3$

Step 3: Multiply the GCF of 44, 22, 11 and GCF of $c^5, c^3 , c^4$

$\text{ GCF of } 44c^5, 22c^3 , 11c^4 = 11 \times c^3 = 11c^3$

Thus $\text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3$

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3 years ago

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k0ka [10]

Answer:

The answer is mean

Step-by-step explanation:

The mean is the average cost of the socks, so finding the mean of both would give an average price to compare them to. :)

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Leokris [45]

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By doing it

Step-by-step explanation:

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Rudiy27

Step-by-step explanation:

Using absolute value to tell wether the sum of two integers is positive or negative.

Suppose we have a positive integer,

x and a negative interger, -x and we want to find their sum, we take the absolute values of each of the integers, that is |x| and |-x|. Then we subtract these values: |x| - |-x|. If the larger integer is positive, the result of the difference is positive, but if the larger number is negative, the result of the difference is negative.

For any integer x, x + (-x) = 0

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