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Keith_Richards [23]
3 years ago
11

Given R=0.0821L⋅atm / mol⋅K, what is the volume of mole of gas at a pressure of 3.12 atm and a temperature of 270K?

Mathematics
2 answers:
WITCHER [35]3 years ago
7 0

Answer:

7.10 L/mol

Step-by-step explanation:

anyanavicka [17]3 years ago
4 0

Answer: the answer is 7.10, B

Step-by-step explanation:

Basically you multiply 0.0821 and the temperature 270K together to get 22.167. Then you divide that by the atm of 3.12 to get 7.10.

(if it helps I also took the test and that was the correct answer.)

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