Answer:
Step-by-step explanation:
a) the equation representing the parabola is expressed as
h = -16t² - 4t + 20
c) to determine the height after 25 seconds, we would substitute 25 for t into the given equation. It becomes
h = -16(25)² - 4(25) + 20
h = - 10000 - 100 + 20
h = - 10080
d) when the coin lands on the ground, the height would be 0. Therefore,
-16t² - 4t + 20 = 0
Dividing both sides of the equation by 4, it becomes
- 4t² - t + 5 = 0
- 4t² - 5t + 4t + 5 = 0
- t(4t + 5) + 1(4t + 5) = 0
- t + 1 = 0 or 4t + 5 = 0
t = 1 or t = - 5/4
Since t cannot be negative, then t = 1 second
In the table, you can see level 1 is 5 to the first power, level 2 is 5 to the second and go on.
so in level 6 would be 5 to the sixth power
so the answer to first one is 5^6
for the second question you should know that level 2 is 5^2 and level 6 is 5^6 so 5^6/5^2 = 5^4 is the answer :))))
I hope this is helpful
have a nice day
Answer:
True
Step-by-step explanation:
Answer:
The correct answer is x = 3 and y = 2.
Step-by-step explanation:
There are many ways to solve systems of equations like this, but I'm going to use substitution. This means taking the value of y given by the second equation and plugging it into the first equation. This is modeled below:
2x - y = 4
2x - (-2x+8) = 4
Now, we can simplify the left side of the equation.
2x + 2x - 8 = 4
4x - 8 = 4
We should add 8 to both sides as the next step.
4x = 12
Now we can divide by 4.
x = 3
To solve for y, we can substitute this value found for x back into either one of our original equations.
y = -2x + 8
y = (-2*3) + 8
y = -6 + 8
y = 2
Therefore, the correct answer is x = 3 and y = 2.
Hope this helps!
((3x^2)^a - (4y^a)(z^3a))^2
First, expand.
((3x^2)^a - (4y^a)(z^3a)) ((3x^2)^a - (4y^a)(z^3a))
Combine
3^(2a) - x^(4a) - 8 * 3^(2a)x^(2a)y^(a)z^(3a) + 16y^(3a)z^(6a)
hope this helps
