How are energy, heat, and temperature related to each other?

Click on the box to choose which compound has a greater difference in electronegativities of its members. Use the

4vir4ik [10]

Answer:

See the example below.

Explanation:

Let us make an example with a group of compounds to apply the general trends of electronegativities within families to find which compound has a greater difference in electronegativities.

Use this group.

a. HBr

b. HI

c. HF

d. HCl

e. H₂

Br, I, F, and Cl belong to the halogen family (group or column 17 of the periodic table).

Electronegativity is a relative measure of how strong an atom atracts the bonding electrons in a compound.

Since the strength of attracion of the valence electrons by the nucleus of an atom decreases as the size of the atom incease, in a family of elements (same group) the electronegativity decreases as you go down in the group.

The order of the halogens from top to bottom in the column in the periodic table is F, Cl, Br, and I.

Thus, the order of their electronegativiies is: F > Cl > Br > I. F is the most electronegative atom, and all those elements have higher electronegativy than H. (The electronegativiy of I is 2.66 and the electronegativity of H is 2.2). Thus, including H, the rank of the electronegativities is F > Cl > Br > I > H.

Thus, the greater difference in electronegativities is for HF (option a.).

Note, that the difference in electronegativites of the atoms of the molecule H₂ is zero, since both atoms have the same electronegativity.

3 0

2 years ago

Read 2 more answers

How many liters of 1.0 M HCl do you need to neutralize 2.0 L of 3.0 M NaOH? How many liters of 1.0 M HCl do you need to neutrali

Kruka [31]

Answer:

For 1: The volume of HCl required is 6 L.

For 2: The volume of HCl required is 9 L.

For 3: The volume of sulfuric acid required is 4.5 L.

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$ ......(1)

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base

For 1:

We are given:

$n_1=1\\M_1=1M\\V_1=?L\\n_2=1\\M_2=3.0M\\V_2=2.0L$

Putting values in equation 1, we get:

$1\times 1\times V_1=1\times 3\times 2\\\\V_1=6L$

Hence, the volume of HCl required is 6 L.

For 2:

We are given:

$n_1=1\\M_1=1M\\V_1=?L\\n_2=2\\M_2=3.0M\\V_2=1.5L$

Putting values in equation 1, we get:

$1\times 1\times V_1=2\times 3.0\times 1.5\\\\V_1=9L$

Hence, the volume of HCl required is 9 L.

For 3:

To calculate the volume of acid, we use the equation:

$N_1V_1=N_2V_2$

where,

$N_1\text{ and }V_1$ are the normality and volume of acid

$N_2\text{ and }V_2$ are the normality and volume of base

We are given:

$N_1=1.0N\\V_1=?L\\N_2=3.0N\\V_2=1.5L$

Putting values in above equation, we get:

$1.0\times V_1=3.0\times 1.5\\\\V_1=4.5L$

Hence, the volume of sulfuric acid required is 4.5 L.

8 0

2 years ago

How long does Neptune take to rotate on its axis?

Ray Of Light [21]

23.934 Hours Is how long it tales.

8 0

2 years ago

What is the molecular geometry of co32-

Rudik [331]

Mark as brainliest...☺

5 0

2 years ago

`Suppose you have a sample of NaOH (0.0315 L, to be exact). If this amount of NaOH is used to exactly titrate 0.0250 L of HCl th

yuradex [85]

Answer:

0.0835 M

Explanation:

Step 1: Write the balanced equation

NaOH + HCl ⇒ NaCl + H₂O

Step 2: Calculate the reacting moles of HCl

0.0250 L of 0.105 M HCl react.

0.0250 L × 0.105 mol/L = 2.63 × 10⁻³ mol

Step 3: Calculate the reacting moles of NaOH

The molar ratio of NaOH to HCl is 1:1. The reacting moles of NaOH are 1/1 × 2.63 × 10⁻³ mol = 2.63 × 10⁻³ mol.

Step 4: Calculate the molarity of NaOH

2.63 × 10⁻³ moles of NaOH are in 0.0315 L of solution.

M = 2.63 × 10⁻³ mol / 0.0315 L = 0.0835 M

7 0

2 years ago