Answer:
[C₆H₅NH₃⁺] = 0.0399 M
Explanation:
This excersise can be easily solved by the Henderson Hasselbach equation
C₆H₅NH₃Cl → C₆H₅NH₃⁺ + Cl⁻
pOH = pKb + log (salt/base)
As we have value of pH, we need to determine the pOH
14 - pH = pOH
pOH = 8.43 (14 - 5.57)
Now we replace data:
pOH = pKb + log ( C₆H₅NH₃⁺/ C₆H₅NH₂ )
8.43 = 9.13 + log ( C₆H₅NH₃⁺ / 0.2 )
-0.7 = log ( C₆H₅NH₃⁺ / 0.2 )
10⁻⁰'⁷ = C₆H₅NH₃⁺ / 0.2
0.19952 = C₆H₅NH₃⁺ / 0.2
C₆H₅NH₃⁺ = 0.19952 . 0.2 = 0.0399 M
Answer:
D. As one variable increases, the other variable also increases
Starch is a polysaccharides which is made up of a long chain of glucose. The sub units that for starch are GLUCOSE. The long chains of glucose in starch are connected by alpha 1,4 linkages. The simplest starch in existence is amylose.
<span>Welding in confined spaces or on stainless steel generates (B) Hexavalent Chromium a very toxic chemical. Hexavalent chromium are chemical compounds that has a chromium with an oxidation state of +6. It is commonly used in textile dyes and wood preservation to avoid corrosion and conversion coatings.</span>
