How many moles are 1.806 x 10^24 atoms?
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Answer:The approximate atomic mass of lead is 207.24 amu.
Explanation:
Abundance of isotope (I) = 1.4% = 0.014
Atomic mass of the Isotope (I) = number protons + number of neutrons = 82 + 122 = 204 amu
Abundance of isotope (II) = 22.1 % = 0.221
Atomic mass of the Isotope (II) = number protons + number of neutrons = 82 + 125 = 207 amu
Abundance of isotope (III) = 24.1% = 0.241
Atomic mass of the Isotope (III) = number protons + number of neutrons = 82 + 124 = 206 amu
Abundance of isotope (IV) = 52.4% = 0.524
Atomic mass of the Isotope (IV) = number protons + number of neutrons = 82 + 126 = 208 amu
Average atomic mass of an element =
Average atomic mass of lead =
The approximate atomic mass of lead is 207.24 amu.
The molality of the toluene is 1.46 mol/kg.
<h3>What is molality?</h3>The molality of a solution is its molal concentration. Molal concentration is denoted by m. It is the mol of solute dissolves in 1 Kg solvent.
The depression at freezing point is directly proportional to the molality of the solution. The equation we use for this type of problem is:
ΔT=iKm
Where, ΔT is depression at freezing point, i is Van't hoff factor, m is molality and
is the freezing point depression constant.
Toluene is a non-electrolyte and so the value of i for this is 1.
Depression at a freezing point is given as -13. and the
is given as 5.12. So, we could calculate the molality of the solution using the equation written above.
Let's plug in the values in the equation:
ΔT=iKm
-7.51 =1 x5. 12 xm
m =
m = 1.46 m
It means the molality of the solution is 1.46 mol/kg.
Hence, the molality of the solution is 1.46 mol/kg.
Learn more about the molality of the solution here:
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