Answer:
(12.1409, 14.0591
Step-by-step explanation:
Given that Tensile strength tests were performed on two different grades of aluminum spars used in manufacturing the wing of a commercial transport aircraft. From past experience with the spar manufacturing process and the testing procedure, the standard deviations of tensile strengths are assumed to be known.
Group Group One Group Two
Mean 87.600 74.500
SD 1.000 1.500
SEM 0.316 0.433
N 10 12
The mean of Group One minus Group Two equals 13.100
standard error of difference = 0.556
90% confidence interval of this difference:

t = 23.5520
df = 20
Answer:
8
Step-by-step explanation:
This one is similar to the other one done with graphs , the only difference is we have equations instead of graphs.
Like the other one, we want to find f(2) and whatever that equals we plug into g(x) to find g(f(2))
So first lets find f(2)
f(x) = x - 4
f(2) = 2 - 4
f(2) = -2
g(f(2)) , f(2) = -2 , g(-2)
now lets find g(-2)
g(x) = -2x + 4
g(-2) = -2(-2) + 4
multiply -2 and -2 to get 4
g(-2) = 4 + 4
add 4 and 4 to get 8
g(-2) = 8
We can conclude that g(f(2)) = 8
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Answer:
Domain (-12,-8,0,1) range (0,8,12)
Booster's share =y =0.75x
gross receipts=x=700
plug x=700 in y=0.75x
y=0.75*700
y=525