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Hope thia helped can you mark me brainliest please
Let Ch and C denote the events of a student receiving an A in <u>ch</u>emistry or <u>c</u>alculus, respectively. We're given that
P(Ch) = 88/520
P(C) = 76/520
P(Ch and C) = 31/520
and we want to find P(Ch or C).
Using the inclusion/exclusion principle, we have
P(Ch or C) = P(Ch) + P(C) - P(Ch and C)
P(Ch or C) = 88/520 + 76/520 - 31/520
P(Ch or C) = 133/520
Answer:
Step-by-step explanation:
si... yono em usho de cmopu preo sloo estoy usand una jjssjsjsj jsjsj c
Answer:
The number of ways this can be done is 1,260 ways
Step-by-step explanation:
In this question, we are asked to calculate the number of ways in which the letters of the word balloon can be arranged.
To do this, we take into consideration those letters that are repeated and the number of times repeated. The letters are l and o and are repeated two times each.
The number of ways = 7!/2!2! = 5040/4 = 1,260 ways
I suppose you want to know such number. Since we have a two digit number consisting of two consecutive integers, the only possible numbers are:
Since we sorted all the cases out, we simply have to check which one satisfies the requirement. For each number, we'll write four times the the sum of its digits, and add 6, hoping to get the original number.
So, the answer is 34.
