Let's solve your equation step-by-step.
(−
1
/5
)(c)+2+c=
1
/5 (10c−20)
Step 1: Simplify both sides of the equation.
(−
1
/5
)(c)+2+c=
1
/5
(10c−20)
(−
1
/5
)(c)+2+c=(
1
/5
)(10c)+(
1
/5
)(−20) (Distribute)
−1
/5
c+2+c=2c+−4
(
−1
/5
c+c)+(2)=2c−4 (Combine Like Terms)
4
/5
c+2=2c−4
4
/5
c+2=2c−4
Step 2: Subtract 2c from both sides.
4/5
c+2−2c=2c−4−2c
−6
/5
c+2=−4
Step 3: Subtract 2 from both sides.
−6
/5
c+2−2=−4−2
−6
/5
c=−6
Step 4: Multiply both sides by 5/(-6).
(
5
/−6
)*(
−6
/5
c)=(
5
/−6
)*(−6)
c=5
Answer:
c=5
Answer:
9 13/20
Step-by-step explanation:
Answer: (4,-4)
y=-4, x=4
Step-by-step explanation:
-4x=4y
4x-8y=12
-8y=-4x+12 Now I can substitute -4x for 4y
-8y=4y+12
-2y=y+12
-3y=12
y=-4
-4x=4y
-4x=4(-4)
x=4
Answer:
log4x+log4(x-6)=2
place under single log using multiplication rule
log4(x(x-6))=2
convert to exponential form:(base(4) raised to log of number(2)=number(x(x-6)
4^2=x(x-6)
16=x^2-6x
x^2-6x-16=0
(x-8)(x+2)=0
x=8
or
x=-2 (reject, x>0)
Step-by-step explanation:
