Evaluate the integral 1 / (x^2 + 9) ^3/2 dx.
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Answer:
No, proportional relations are of the form,
Step-by-step explanation:
The given equation is
This is an equation in the form:
since we can rewrite to get:
This equation has a non-zero y-intercept and does not pass through the origin.
A proportional relation, will have a zero y-intercept and pass through the origin.
Therefore a proportional relation is of the form,
First cross out the -6 and -36. Six will go into 6 one time and 6 will go into -36 six times so we have the following after crossing out.
Next cross out the x / x^2 which will give us the following:
Now cross out the y^2 / y^3
All that is left is to cross out the z^5 / z^4 and we are done.