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vazorg [7]
3 years ago
7

Simplify 6(x+4)=-2(4x-4)+8x

Mathematics
1 answer:
AveGali [126]3 years ago
3 0

\huge\mathscr{\colorbox{blue}{\color{yellow}{Answer:}}}

\large{\rightarrow{6\:(x\:+\:4)\:=\:-\:2\:(4x\:-\:4)\:+\:8x}}

\large{\rightarrow{6\:(x\:+\:4)\:=\:-\:2\:(4x\:-\:4)\:+\:8x}}

\large{\rightarrow{6x\:+\:24\:=\:-\:8x\:+\:8\:+\:8x}}

\large{\rightarrow{6x\:+\:24\:=\:{\cancel{-\:8x}}\:+\:8\:+{\cancel{\:8x}}}}

\large{\rightarrow{6x\:+\:24\:=\:8}}

\large{\rightarrow{6x\:=\:8\:-\:24}}

\large{\rightarrow{6x\:=\:16}}

\large{\rightarrow{x\:=\:\frac{-\:16}{6}}}\\

\large\pink{\boxed{\color{lime}{\rightarrow{x\:=\:\frac{-\:8}{3}}}}}\\

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The second-order equation as its equivalent system of first-order equations is

\left[\begin{array}{ccc}u(1)\\\\v(1)\end{array}\right] = \left[\begin{array}{ccc}7.5\\\\9\end{array}\right]

An equivalent system that has the identical answer is known as an equivalent structure. Given a gadget of two equations, we can produce an equal system by way of replacing one equation by means of the sum of the 2 equations, or by way of changing an equation by means of a couple of of itself.

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Taking v = u, we have:

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So we can write it as:

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So the initial condition matrix is:

\left[\begin{array}{ccc}u(1)\\\\v(1)\end{array}\right] = \left[\begin{array}{ccc}7.5\\\\9\end{array}\right]

Learn  more about the equivalent system here brainly.com/question/14878855

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