What is the least common multiple of 9 3 and 12

Mathematics

2 answers:

Naya [18.7K]2 years ago

6 0

Answer:

the least or lowest common multiple is 36

Step-by-step explanation:

9x4=36

3x12=36

12x3=36

julsineya [31]2 years ago

3 0

Answer:

Step-by-step explanation:

9 x 4 = 36

3 x 12 = 36

12 x 3 = 36

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Part A: Factor x2b2 − xb2 − 6b2. Show your work. (4 points)

IrinaVladis [17]

PART A. Notice that we have $b^{2}$ as a common factor in all the terms, so lets factor that out:
$x^{2} b^2-xb^2-6b^2$
$b^2(x^{2} -x-6)$
Now we need can factor $x^{2} -x-6$ :
$b^2(x^{2} -x-6)$
$b^2(x+2)(x-3)$

We can conclude that the complete factorization of $x^{2} b^2-xb^2-6b^2$ is $b^2(x+2)(x-3)$ .

PART 2. Here we just have a quadratic expression of the form $a x^{2} +bx+c$ . To factor it, we are going to find two numbers that will multiply to be equal the c, and will also add up to equal b. Those numbers are 2 and 2:
 $x^{2} +4x+4=(x+2)(x+2)$
Since both factors are equal, we can factor the expression even more:
$x^{2} +4x+4=(x+2)^2$

We can conclude that the complete factorization of $x^{2} +4x+4$ is $(x+2)^2$ .

PART C. Here we have a difference of squares. Notice that 4, can be written as $2^2$ , so we can rewrite our expression:
$x^2-4=x^2-2^2$
Now we can factor our difference of squares like follows:
$x^{2} -2^2=(x+2)(x-2)$

We can conclude that the complete factorization of $x^2-4$ is $(x+2)(x-2)$