3 years ago

Anyone know this geometry question? Will give brainiest

1 answer:

5 0

The opposite angles equal each other, so X and Z are equal
using that we solve for x by setting them equal:

6x-60 = 2x+68

subtract 2x from each side:

4x -60 = 68

add 60 to each side:

4x = 128
divide both sides by 4
x = 128/4
x = 32

now we know x so we can solve everything else by replacing x with 32

WY = 3x+5 = 3(32)+5 = 96+5 = 101

angle Z = 2x+68 = 2(32)+68 = 64+132

the answer is C

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I the equation 3x^2+6x=12, the value of c is?

ozzi

Answer:

c = -12

Step-by-step explanation:

Quadratic Standard Form: ax² + bx + c

Step 1: Write equation

3x² + 6x = 12

Step 2: Subtract 12 on both sides

3x² + 6x - 12 = 0

Here, we have the standard form of the quadratic. We see that our c = -12