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2 years ago

Write any two necessary condition for collinearity.

Mathematics

1 answer:

Zolol [24]2 years ago

6 0

Collinear points: Three points A, B and C are said to be collinear if they lie on the same straight line.

There points A, B and C will be collinear if AB + BC = AC as is clear from the adjoining figure.

In general, three points A, B and C are collinear if the sum of the lengths of any two line segments among AB, BC and CA is equal to the length of the remaining line segment, that is, either AB + BC = AC or AC +CB = AB or BA + AC = BC.

In other words,

There points A, B and C are collinear if:

(i) AB + BC = AC i.e.,

Or, (ii) AB + AC = BC i.e. ,

Or, AC + BC = AB i.e.,

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What is the coordinate of point P on the line segment AB that is 3/4 of the distance from A to B for A(2,5) and B(6,9)?

Brut [27]

Answer:

p is (3.71, 6.71)

Step-by-step explanation:

Given that p is at the distance of 3/4 from A to B

it mean that point p divides the line AB into 3:4 ratio.

and

if there are two points (x1,y1) and (x2,y22) which is divided by point p in the ratio m:n then

coordinates of point p (x,y) is given

p (x = (n*x1+m*x2)/m+n , y = (n*y1+m*y2)/m+n )

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Given the points AB

A(2,5)

B(6,9)

m:n = 3:4

thus,

p (x = (4*2+3*6)/7 , y = (4*5+3*9)/7 )

p (x = (26/7 , y = 47/7 )

P ( x = 3.71, y = 6.71)

Thus, coordinates of point p is (3.71, 6.71) which is at 3/4 of the distance from A to B for A(2,5) and B(6,9)/

5 0

2 years ago

Express sin A,cos A and tan A as ratios

OverLord2011 [107]

Answer:

Part A) $sin(A)=\frac{2\sqrt{42}}{23}$

Part B) $cos(A)=\frac{19}{23}$

Part C) $tan(A)=\frac{2\sqrt{42}}{19}$

Step-by-step explanation:

Part A) we know that

In the right triangle ABC of the figure the sine of angle A is equal to divide the opposite side angle A by the hypotenuse

$sin(A)=\frac{BC}{AB}$

substitute the values

$sin(A)=\frac{2\sqrt{42}}{23}$

Part B) we know that

In the right triangle ABC of the figure the cosine of angle A is equal to divide the adjacent side angle A by the hypotenuse

$cos(A)=\frac{AC}{AB}$

substitute the values

$cos(A)=\frac{19}{23}$

Part C) we know that

In the right triangle ABC of the figure the tangent of angle A is equal to divide the opposite side angle A by the adjacent side angle A

$tan(A)=\frac{BC}{AC}$

substitute the values

$tan(A)=\frac{2\sqrt{42}}{19}$

8 0

2 years ago

What is the midpoint M of that line segment?

topjm [15]

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ T(\stackrel{x_1}{6}~,~\stackrel{y_1}{3})\qquad U(\stackrel{x_2}{6}~,~\stackrel{y_2}{9}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{6+6}{2}~~,~~\cfrac{9+3}{2} \right)\implies \left( \cfrac{12}{2}~~,~~\cfrac{12}{2} \right)\implies \stackrel{M}{(6,6)}$

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3 years ago

I WILL GIVE BRAINLIEST!!

m_a_m_a [10]

Answer:

Step-by-step explanation:

The problem is basically asking us to find the value on the graph corresponding to the x value of 1. We can draw a line with the equation x = 1(or just trace your finger up) to see that when x = 1, the output of the function is at the value 1 as well(the y value).

3 0

3 years ago

The total cost of a jacket and a pair of pants was $66.12. If the price of the jacket was $3.26 less than the pair of pants, wha

drek231 [11]

Answer:

The price of the jacket was $31.43

Step-by-step explanation:

Let the cost of a jacket = x

Let the cost of a pair of pants = y

Such that,

x + y = $66.12.........Equation 1.

From the conditional statement,

x = y - $3.26..........Equation 2.

Solve both equations simultaneously, using the substitution method

From Equation 2;

x = y - 3.26

Substitute y - 3.26 for x in Equation 1.

x + y = 66.12, now becomes,

y - 3.26 + y = 66.12

collect like terms

y + y = 66.12 + 3.26

2y = 69.36

y= 69.36/2 = $34.69.

Put y = $34.69 in Equation 2. to obtain x

x = 34.69 - 3.26

x = $31.43

4 0

2 years ago

Write any two necessary condition for collinearity. ​

Write any two necessary condition for collinearity.