Answer:
a) there is s such that <u>r>s</u> and s is <u>positive</u>
b) For any <u>r>0</u> , <u>there exists s>0</u> such that s<r
Step-by-step explanation:
a) We are given a positive real number r. We need to wite that there is a positive real number that is smaller. Call that number s. Then r>s (this is equivalent to s<r, s is smaller than r) and s is positive (or s>0 if you prefer). We fill in the blanks using the bold words.
b) The last part claims that s<r, that is, s is smaller than r. We know that this must happen for all posirive real numbers r, that is, for any r>0, there is some positive s such that s<r. In other words, there exists s>0 such that s<r.
Answer:
multiply 9 from m and -3
9m - 27 + 3m = 7m + 43
12m - 27 = 7m + 43
12m - 7m = 43+ 27
5m = 70 cut 70 by 5 in 14 times [ 14 x 5= 70 ]
m = 14 answer ❤️❤️ it is 100% correct now!
5 x 3 = 15 is this correct
Answer:
Divided into five equal parts
Answer:

Step-by-step explanation:
we know that
The probability that it will hit a point in the outer (yellow) ring is equal to divide the area of the yellow ring by the total area of the target
step 1
Find the area of the yellow ring
![A=\pi [7^{2} -5^{2}]](https://tex.z-dn.net/?f=A%3D%5Cpi%20%5B7%5E%7B2%7D%20-5%5E%7B2%7D%5D)

step 2
Find the total area of the target
![A=\pi [7^{2}]](https://tex.z-dn.net/?f=A%3D%5Cpi%20%5B7%5E%7B2%7D%5D)

step 3
Find the probability

Convert to percentage
