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Arada [10]
3 years ago
5

You have to solve the problems starting at the "begin" and make your way up to the "end". The correct answer is one of the probl

ems surrounding the problem at hand, (VERY IMPORTANT) PLEASE show you work for each problem. You dont have to right me a essay, just have part of your work shown.

Mathematics
2 answers:
Thepotemich [5.8K]3 years ago
6 0
Begin
3x-4=14
3x=18
x=6

.5n=1.25
n=2.5

x+1=2x-2
x+3=2x
3=x

x+3=10
x=7

6x-13=-11
6x=2
x=1/3

p=4-p
2p=4
p=2

End
Mekhanik [1.2K]3 years ago
5 0
Explained above, wish i could’ve helped, but if you need help respond to this comment please
You might be interested in
Conjectures can always be proven true.<br> True or False
DochEvi [55]
Yes, It is True first find what is a conjectures
4 0
4 years ago
Read 2 more answers
Two bowls and one cup weigh 800 grams. One bowl and two cups weigh 700 grams. Find the weight of the bowl and the cup
antoniya [11.8K]

Answer:

\large \boxed{\textbf{Bowl = 300 g; cup = 200 g}}  

Step-by-step explanation:

 Let b  = the mass of a bowl  

and c = the mass of a cup  

We have two conditions:  

\begin{array}{lrcl}(1) &2b + c  & = & 800\\(2) & b + 2c & = & 700\\\end{array}

Calculations:  

\begin{array}{lrcll}(3) & 4b + 2c &=  & 1600&\text{ Multiplied (1) by 2}\\& 3b & = & 900&\text{Subtracted (2) from (3)}\\(4) & b & = & \mathbf{300}&\text{Divided each side by 3}\\ & 600 + c & = & 800&\text{Substituted (4) into (2}\\ & c & = & \mathbf{200}\\\end{array}\\\text{The mass of a bowl  is $\large \boxed{\textbf{300 g}}$ and that of a cup is $\large \boxed{\textbf{200 g}}$}

Check:

\begin{array}{rlcrl}2(300) + 200& =800 & & 300 + 2(200) & = 700\\600 + 200 & = 800& & 300 + 400 & = 700\\800 & = 800& & 700 & = 700\\\end{array}

OK.

6 0
3 years ago
Someone please help me on this question ?:)
Whitepunk [10]

C  ,      a relationship between two variables can be expressed by an equation in which one variable is equal to a constant.

8 0
3 years ago
Need help please. I don't know
Natali [406]
f(3)=3+1=4
6 0
4 years ago
4) Adult tickets for the evening show at XD Theater are $11 and children's tickets are $Belf the theater seats 250 people, how m
kozerog [31]

Omitted value: The price of children ticket was omitted in the question, so i used $8 to solve. You can input the correct value and solve the same way following the steps.

Answer: 100 adult tickets  must be sold.

Step-by-step explanation:

step 1

let  x represent Adults

AND y represent children

Since the theater seats 250 people we have that

x+y = 250..... equation 1

Also price for Adult ticket = $11

and  price children ticket =$8

With total sales at $2,300, we have that

11x + 8y= 2300----- equation 2

Step 2

Making y subject in equation 1

' x+y = 250

y= 250-x

Putting y= 250- x in equation 2

11x + 8(250-x)= 2300

11x +2000-8x= 2300

11x -8x = 2300-2000

3x= 300

x 300/3

x= 100.

To find y

 x+y = 250

100+y=250

y=250-100

y=150

Therefore 100 adult tickets and 150 children tickets must be sold to get a total sales of $2,300

5 0
3 years ago
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