Not sure what you mean by drag and drop but Im going to attempt this.
-3/5 = -12/20
1/5 = 4/20
That makes no sense. It should be -8/20 < 7/20?
It will be whichever equation you see that has the "c" = +3, in the format:
F(x) = y = ax^2 + bx + c, where a, b, and c are all integers, such that plugging a "0" into the x's will give:
y = a•0^2 + b•0 + 3 = 0 + 0 + 3 = 3
Answer:
Step-by-step explanation:
Answer:
- number of multiplies is n!
- n=10, 3.6 ms
- n=15, 21.8 min
- n=20, 77.09 yr
- n=25, 4.9×10^8 yr
Step-by-step explanation:
Expansion of a 2×2 determinant requires 2 multiplications. Expansion of an n×n determinant multiplies each of the n elements of a row or column by its (n-1)×(n-1) cofactor determinant. Then the number of multiplies is ...
mpy[n] = n·mp[n-1]
mpy[2] = 2
So, ...
mpy[n] = n! . . . n ≥ 2
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If each multiplication takes 1 nanosecond, then a 10×10 matrix requires ...
10! × 10^-9 s ≈ 0.0036288 s ≈ 0.004 s . . . for 10×10
Then the larger matrices take ...
n=15, 15! × 10^-9 ≈ 1307.67 s ≈ 21.8 min
n=20, 20! × 10^-9 ≈ 2.4329×10^9 s ≈ 77.09 years
n=25, 25! × 10^-9 ≈ 1.55112×10^16 s ≈ 4.915×10^8 years
_____
For the shorter time periods (less than 100 years), we use 365.25 days per year.
For the longer time periods (more than 400 years), we use 365.2425 days per year.
<span>Price of the dishwashers on sale are represented with the function: p ( d ) = 0.75 d ( 100 % - 25 % = 75 % or 0.75 d ): After that we have additional 14 % on the discounted price ( 100 % + 14 % = 114 % OR 1.14 ): C ( P ) = 1.14 P. Finally, c ( p ( d ) ) = 1.14 * 0.75 d = 0.855 d. Answer: C ) c [ p ( d ) ] = 0.855 d Hope I helped! :) Cheers!</span>
