Answer:
<h2>A. 4t² - 32t + 64</h2>
Step-by-step explanation:
Instead of x put (t - 3) in the equation of the function f(x) = 4x² - 8x + 4:
f(t - 3) = 4(t - 3)² - 8(t - 3) + 4
<em>use (a - b)² = a² - 2ab + b² and the distributive property a(b + c) = ab + ac</em>
f(t - 3) = 4(t² - (2)(t)(3) + 3²) + (-8)(t) + (-8)(-3) + 4
f(t - 3) = 4(t² - 6t + 9) - 8t + 24 + 4
f(t - 3) = (4)(t²) + (4)(-6t) + (4)(9) - 8t + 28
f(t - 3) = 4t² - 24t + 36 - 8t + 28
f(t - 3) = 4t² + (-24t - 8t) + (36 + 28)
f(t - 3) = 4t² - 32t + 64
Answer:
Step-by-step explanation:
f * g = (x^2 + 3x - 4) (x+4)
open bracket
x((x^2 + 3x - 4) + 4 (x^2 + 3x - 4)
x³ +3x²-4x+x²+12x-16
x³+3x²+x²-4x+12x-16
x³+4x²+8x-16 (domain is all real numbers.
f/g = (x^2 + 3x - 4)/(x+4)
factorising (x^2 + 3x - 4)
x²+4x-x_4
x(x+4) -1 (x+4)
(x+4)(x-1)
f/g = (x^2 + 3x - 4)/(x+4) =(x+4)(x-1)/(x+4) = (x-1)
Before factorisation, this was a rational function so the domain is all real numbers excluding any value that would make the denominator equal zero.
Hence I got x - 1, and x cannot equal -4
So the domain is just all real numbers without -4
(13/20)=(x/152)
1976=20x
x=98.8
About 99 have dogs
Answer:
....bbbbbb.... its correct
1. Write as an algebraic equation:
12 + n ≤ 2n - 8
2. Solve for n.
12 + n - 12 ≤ 2n - 8 - 12
n ≤ 2n - 20
n - 2n ≤ 2n - 20 - 2n
-n ≤ -20
Multiply both sides by -1 (this means you must flip the inequality sign).
n ≥ 20
FINAL ANSWER: n ≥ 20
Hope this helps! Feel free to ask for clarification.
