<span>Consider a angle â BAC and the point D on its defector
Assume that DB is perpendicular to AB and DC is perpendicular to AC.
Lets prove DB and DC are congruent (that is point D is equidistant from sides of an angle â BAC
Proof
Consider triangles ΔADB and ΔADC
Both are right angle, â ABD= â ACD=90 degree
They have congruent acute angle â BAD and â CAD( since AD is angle bisector)
They share hypotenuse AD
therefore these right angle are congruent by two angle and sides and, therefore, their sides DB and DC are congruent too, as luing across congruent angles</span>
Answer:
ok
Step-by-step explanation:
9+10=21
Answer:
Below!
Explanation:
A system of equations with infinite solutions defines that both the equations are identical and are overlapping when the lines are graphed. An example could be y = 5x + 9 and y = 5x + 9. These sets of equations have infinite solutions because they are the same and when graphed, they overlap.
Hoped this helped!
A - 2x^2 + 2x - 2
To find this, set up the equation:
(-x^2 + 6x - 1) + ( 3x^2 - 4x - 1)
With this, you need to combine like terms while taking into consideration the addition sign.
-x^2 + 3x^2 = 2x^2
6x + - 4x = 2x
- 1 + - 1 = - 2
Hope this helps!
