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Maru [420]
4 years ago
14

I need realllll answers and help please

Mathematics
1 answer:
slava [35]4 years ago
4 0
B) 5.4 feet because 32 /2 = 16 and 16 /3=5.4 or 5 & 1/5th
You might be interested in
Find Sn for the given arithmetic series a1=-26 d=-9 n=24
ryzh [129]

Answer:

- 3108

Step-by-step explanation:

The sum to n terms of an arithmetic series is

S_{n} = \frac{n}{2} [ 2a_{1} + (n - 1)d ]

Substitute the given values into the formula

S_{24} = \frac{24}{2} [ (2 × - 26) + (23 × - 9) ]

                          = 12 ( - 52 - 207 )

                         = 12 × - 259 = - 3108

5 0
3 years ago
(5+2g)exp5 for g=-2<br> help pls
Sidana [21]

The value of the expression when g = -2 is -1

<h3>How to simplify the expression</h3>

Given the expression;

(5+2g)exp5

(5+2g)^5

For g = -2

Let's substitute the value of g in the expression

= ( 5 + 2 ( -2) ) ^5

Expand the bracket

= ( 5 - 4) ^ 5

Find the difference

= (-1) ^5

= -1

Thus, the value of the expression when g = -2 is -1

Learn more about algebraic expressions here:

brainly.com/question/4344214

#SPJ1

5 0
1 year ago
PLEASE HELP I'M CONFUSED! The measures of two adjacent angles have a ratio of 3:5. The sum of the measures of the two adjacent a
Paraphin [41]
75<span>°. So divide 120 by 8, then multiply 8 with 15. That's the measure of the larger angle. </span>
5 0
3 years ago
Read 2 more answers
Which of the following fractions has the same value as the decimal number 0.65?
boyakko [2]

Answer:

13/20

Step-by-step explanation:

To find this, divide 13 by 20 to get .65

Hope this helped!

4 0
3 years ago
Write and equati9n of a l8ne that passes through (1,-2) and is perpendicular to -4x+7y=21
yarga [219]

Given:

A line passes through (1,-2) and is perpendicular to -4x+7y=21.

To find:

The equation of that line.

Solution:

We have, equation of perpendicular line.

-4x+7y=21

Slope of this line is

m_1=-\dfrac{\text{Coefficient of x}}{\text{Coefficient of y}}

m_1=-\dfrac{-4}{7}

m_1=\dfrac{4}{7}

Product of slope of two perpendicular lines is -1.

m_1\times m_2=-1

\dfrac{4}{7}\times m_2=-1

m_2=-\dfrac{7}{4}

Now, slope of required line is -\dfrac{7}{4} and it passes through (1,-2). So, the equation of line is

y-y_1=m(x-x_1)

where, m is slope.

y-(-2)=-\dfrac{7}{4}(x-1)

4(y+2)=-7(x-1)

4y+8=-7x+7

4y+7x=7-8

7x+4y=-1

Therefore, the equation of required line is 7x+4y=-1.

7 0
3 years ago
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