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2 years ago

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A line goes through the points (4, 5) and (2, -6). Write the equation of the line in point-slope form. Show your work for full c

redit. (Show how you went from those two points to having the equation in point-slope form?) Circle your answer (4 points)

1 answer:

ehidna [41]2 years ago

4 0

Answer:

y = 5.5x – 17

Step-by-step explanation:

Slope (m) = ΔY/ΔX=11/2 =5.5

When x=0, y = -17

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Consider the following graph of two functions,S(1) + 8(2)Step 1 of 2: Finds (1) + 8(2)Enable Zoom/Pan8(x) = x2 - 2x - 1S(x) = -x

kumpel [21]

.Given:

$\begin{gathered} f(x)=-x+1 \\ g(x)=x^2-2x-1 \end{gathered}$

ToDetermine: The value of

$f(1)+g(2)$

Solution

$\begin{gathered} f(x)=-x+1 \\ f(1)=-1+1 \\ f(1)=0 \end{gathered}$ $\begin{gathered} g(x)=x^2-2x-1 \\ g(2)=(2)^2-2(2)-1 \\ g(2)=4-4-1 \\ g(2)=-1 \\ f(1)+g(2)=0+(-1) \\ f(1)+g(2)=-1 \end{gathered}$

Hence, f(1) + g(2) = -1

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1 year ago

To one-one functions g and h are defined as follows.

Andreyy89

Answer:

9
(x-8)/3
-1

Step-by-step explanation:

The inverse function for a set of ordered pairs can be found by swapping the x- and y-coordinates in each pair.

$g^{-1}(-1)=9\qquad\text{from the $g(x)$ ordered pair $(9, -1)$}$

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The inverse of a function expressed algebraically can be found by swapping the x- and y-variables and solving for y.

$h^{-1}(x)\qquad\text{is found from }x=h(y)\\\\x=3y+8\\x-8=3y\\\\y=\dfrac{x-8}{3}\\\\\boxed{h^{-1}(x)=\dfrac{x-8}{3}}$

A function of its own inverse returns the original value:

$\boxed{\left(h\circ h^{-1}\right)(-1)=-1}$

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3 years ago

Find the distance between Points C(4, 6) and D(−5, 6) without using a coordinate plane.

balu736 [363]

Answer:

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Step-by-step explanation:

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3 years ago

What is the inverse of function f?<br> f(x)=64x^3-1

Yuri [45]

The inverse for function of f ⬇️

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3 years ago

Read 2 more answers

Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in s

Jobisdone [24]

Answer:

$f(x)=x^4-9x^2-50x-150$

Step-by-step explanation:

Let f(x) be the polynomial function of minimum degree with real coefficients whose zeros are 5, -3, and -1 + 3i be f(x).

By the complex conjugate property of polynomials, -1-3i is also a root of this polynomial.

Therefore the polynomial in factored form is $f(x)=(x-5)(x+3)(x-(-1+3i))(x-(-1+3i))$

We expand to get: $f(x)=(x^2-2x-15)(x^2+2x+10)$

We expand further to get:\

$f(x)=x^4-9x^2-50x-150$

3 0

3 years ago