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3 years ago

What needs to be applied in order to change an object's momentum?

Physics

1 answer:

Veseljchak [2.6K]3 years ago

3 0

Answer:

Explanation:

if you want to change an object's momentum you need to apply force to the object

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Calculate the angular velocity of the earth in its orbit around the sun.

Orlov [11]

Answer:

$0.0172rad/day=1.99x10^{-7}rad/second$

Explanation:

The definition of angular velocity is as follows:

$\omega=2\pi f$

where $\omega$ is the angular velocity, and $f$ is the frequency.

Frequency can also be represented as:

$f=\frac{1}{T}$

where $T$ is the period, (the time it takes to conclude a cycle)

with this, the angular velocity is:

$\omega=\frac{2\pi}{T}$

The period T of rotation around the sun 365 days, thus, the angular velocity:

$\omega=\frac{2\pi}{365days}=0.0172rad/day$

if we want the angular velocity in rad/second, we need to convert the 365 days to seconds:

Firt conveting to hous

$365days(\frac{24hours}{1day} )=8760hours$

then to minutes

$8760hours(\frac{60minutes}{1hour} )=525,600minutes$

and finally to seconds

$525,600minutes(\frac{60seconds}{1minute})=31,536x10^3seconds$

thus, angular velocity in rad/second is:

$\omega=\frac{2\pi}{31,536x10^3seconds}=1.99x10^{-7}rad/second$

3 0

3 years ago

Which of the following correctly describe electric field lines?

Xelga [282]

-- Electric field lines DO never cross. (A)

-- Electric field lines that are close together DO indicate a stronger electric field. (B)

-- Electric field lines DO not affect the charge that created them. (C)

-- Electric field lines DON'T begin on north poles and end on south poles. North and South "poles" are the way we talk about magnets, not electric charges.

6 0

3 years ago

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Would the frequency of the angular simple harmonic motion (SHM) of the balance wheel increase or decrease if the dimensions of t

storchak [24]

Answer:

Yes the frequency of the angular simple harmonic motion (SHM) of the balance wheel increases three times if the dimensions of the balance wheel reduced to one-third of original dimensions.

Explanation:

Considering the complete question attached in figure below.

Time period for balance wheel is:

$T=2\pi\sqrt{\frac{I}{K}}$

$I=mR^{2}$

m = mass of balance wheel

R = radius of balance wheel.

Angular frequency is related to Time period as:

$\omega=\frac{2\pi}{T}\\\omega=\sqrt{\frac{K}{I}} \\\omega=\sqrt{\frac{K}{mR^{2}}$

As dimensions of new balance wheel are one-third of their original values

$R_{new}=\frac{R}{3}$

$\omega_{new}=\sqrt{\frac{K}{mR_{new}^{2}}}\\\\\omega_{new}=\sqrt{\frac{K}{m(\frac{R}{3})^{2}}}\\\\\omega_{new}={3}\sqrt{\frac{K}{mR^{2}}}\\\\\omega_{new}={3}\omega$

5 0

3 years ago

Vector A with arrow, which is directed along an x axis, is to be added to vector B with arrow, which has a magnitude of 5.5 m. T

ohaa [14]

Answer:

Magnitude of vector A = 0.904

Explanation:

Vector A , which is directed along an x axis, that is

$\vec{A}=x_A\hat{i}$

Vector B , which has a magnitude of 5.5 m

$\vec{B}=x_B\hat{i}+y_B\hat{j}$

$\sqrt{x_{B}^{2}+y_{B}^{2}}=5.5\\\\x_{B}^{2}+y_{B}^{2}=30.25$

The sum is a third vector that is directed along the y axis, with a magnitude that is 6.0 times that of vector A $\vec{A}+\vec{B}=6x_A\hat{j}\\\\x_A\hat{i}+x_B\hat{i}+y_B\hat{j}=6x_A\hat{j}$

Comparing we will get

$x_A=-x_B\\\\y_B=6x_A$

Substituting in $x_{B}^{2}+y_{B}^{2}=30.25$

$\left (-x_{A} \right )^{2}+\left (6x_{A} \right )^{2}=30.25\\\\37x_{A}^2=30.25\\\\x_{A}=0.904$

So we have

$\vec{A}=0.904\hat{i}$

Magnitude of vector A = 0.904

8 0

4 years ago

If the sound level at a point is 98.0 dB, what is the intensity of sound at that point (Unit=W/m^2)? please help will give brain

Firlakuza [10]

Answer: The decibel scale is a logarithmic scale where each bel or 10 decibels correspondents to a factor of ten. A power intensity of 10^(-12) watts per square meter is the standard reference for a SPL of 0 db. So an SPL of 98 db corresponds to a power intensity of 10^(9.8)*10^(-12) or 10^(9.8–12) w/m^2.

0.006309573 w/m^2.

You can also readily find the value for any given SPL using the online calculator at: http://www.sengpielaudio.com/calculator-soundlevel.htm

Explanation:

7 0

3 years ago

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