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4 years ago

___________ used math to show that the planets move in ellipses, not perfect circles, around the Sun.

Physics

2 answers:

MariettaO [177]4 years ago

6 0

I believe the answer is A

AleksAgata [21]4 years ago

4 0

Aristotle used <span>math to show that the planets move in ellipses, not perfect circles, around the Sun.
Hope this helps~!
~{Dunsforhands}</span>

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After a party the host pours the remnants of several bottles of wine into a jug. He then inserts a cork with a 2.15-cm diameter

pychu [463]

Answer:

3893.99675 N

Explanation:

$F_1$ = 125 N

$A_1$ = $\pi 1.075^2$

$A_2$ = $\pi 6^2$

From Pascal's law

$\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}\\\Rightarrow F_2=\dfrac{F_1\times A_2}{A_1}\\\Rightarrow F_2=\dfrac{125\times 6^2}{1.075^2}\\\Rightarrow F_2=3893.99675\ N$

The force that the liquid exerts on the bottom of the bottle is 3893.99675 N

5 0

3 years ago

How is velocity different from speed <br>

salantis [7]

Answer: velocity has a direction, while speed is the distance travelled by an object.

Explanation:

7 0

3 years ago

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Calculate the total resistance for a 650ohm , a 350 ohm , and a 1000 ohm resistor connected in series

Mekhanik [1.2K]

Answer:

2000 ohms

Explanation:

Resisters in series just add.

Rt = R1 + R2 + R3

R1 = 650 ohm

R2 = 350 ohm

R3 = 1000 ohm

Rt = 650 + 350 + 1000

Rt = 2000 ohms.

5 0

4 years ago

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A car is making a 60 mi trip. It travels the first half of the total distance 30.0 mi at 8.00 mph and the last half of the total

Alja [10]

Answer:

total time =4.583 hour

Explanation:

We have given total distance = 60 mi

It is given that half of the distance traveled by a speed of 8 mph

We know that $time\ t=\frac{distance }{speed}=\frac{30}{8}=3.75hour$

And second half of the distance traveled by a speed of 36 mph

So time $t=\frac{distance }{speed}=\frac{30}{36}=0.833hour$

So total time = 3.75 + 0.833 =4.583 hour

3 0

4 years ago

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A uniform, solid, 1800.0 kgkg sphere has a radius of 5.00 mm. Find the gravitational force this sphere exerts on a 2.30 kgkg poi

iVinArrow [24]

Answer

given,

Mass of the solid sphere = 1800 Kg

radius of the sphere,R = 5 m

mass of the small sphere, m = 2.30 Kg

when the Point is outside the sphere the Force between them is equal to

$F = \dfrac{GMm}{r^2}$ when r>R

When Point is inside the Sphere

$F = \dfrac{GMm}{R^2}\ \dfrac{r}{R}$ when r<R

where r is the distance where the point mass is placed form the center

Now Force calculation

a) r = 5.05 m

$F = \dfrac{GMm}{r^2}$ [/tex]

$F = \dfrac{6.67\times 10^{-11}\times 1800\times 2.3}{5.05^2}$

F = 1.082 x 10⁻⁸ N

b) r = 2.65 m

$F = \dfrac{GMm}{R^2}\ \dfrac{r}{R}$

$F = \dfrac{6.67\times 10^{-11}\times 1800\times 2.3}{5.05^2}\ \dfrac{2.65}{5.05}$

$F = 5.68\times 10^{-9}\ N$

3 0

3 years ago