Answer:
The volume in such a package is 27648 in³
Step-by-step explanation:
Consider the provided information.
Postal regulations specify that a parcel sent by priority mail may have a combined length and girth of no more than 144 in.
Let the dimension are x by x by y.
Where x is the variable for the square base package and y is the variable for length.
Thus l=x, b=x and h=y
Then the volume of the box is:
(∵V=lbh)
The maximum combined length and girth is 144.
Therefore, 

Substitute the value of y in volume of the box.



Substitute V'(x)=0.



Now apply second derivative test.

(Min)
(Max)
Hence, the maximum volume is at x=24
If x=24 then 
Substituting value of x = 24 and y = 48
gives 27648.
Hence, the volume in such a package is 27648 in³
Step-by-step explanation:




Therefore, N = 1
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Answer:
F = 1.25
Step-by-step explanation:
All you would have to do is cross multiply, so our equations starts at
. We would now multiply F by 8 and 2 by 5. We now have 8F = 10. We can now divide both sides of the equation by 8 to get F = 1.25.