This question not incomplete
Complete Question
The life of a semiconductor laser at a constant power is normally distributed with a mean of 7,000 hours and a standard deviation of 600 hours. If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is closest to? Assuming percentile = 95%
Answer:
0.125
Step-by-step explanation:
Assuming for 95%
z score for 95th percentile = 1.645
We find the Probability using z table.
P(z = 1.645) = P( x ≤ 7000)
= P(x<Z) = 0.95
After 7000 hours = P > 7000
= 1 - P(x < 7000)
= 1 - 0.95
= 0.05
If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is calculated as:
(P > 7000)³
(0.05)³ = 0.125
The answer is B)x+y=y+x.
This is just changing the order of the numbers to get the same equation....\
So for example if I have 2+7 and I use the property of addition It would give me 2+7=7+2.
Pls mark brainliest if this helped!
Answer: c
Step-by-step explanation:
1/18 can't be simplified because 1 cant be simplified. What ever happens to one side of the equation happens to the other, so nothing can happen to the 1 so nothing can happen to the 18
It cant be simplified
Answer:
46
Step-by-step explanation:
It must be the same as the angle opposite of it.
You can see that 134 and 134 are the same, so the other two corners need to be the same and be 46 and 46.
