Answer:
c =0.2 J/g.°C
Explanation:
Given data:
Specific heat of material = ?
Mass of sample = 12 g
Heat absorbed = 48 J
Initial temperature = 20°C
Final temperature = 40°C
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 40°C -20°C
ΔT = 20°C
48 J = 12 g×c×20°C
48 J =240 g.°C×c
c = 48 J/240 g.°C
c =0.2 J/g.°C
Answer:
66.0 mL HClO3
Explanation:
M1V1 = M2V2
M1 = 0.100 M HClO3
V1 = ?
M2 = 0.165 M KOH
V2 = 40.0 mL KOH
Solve for V1 --> V1 = M2V2/M1
V1 = (0.165 M)(40.0 mL) / (0.100 M) = 66.0 mL HClO3
Each column is also called a group. The elements in each group have the same number of electrons in the outer orbital. As you keep counting the columns, you'll know how many electrons are in the outer shell.
Answer:
Explanation:
When gas changes to liquid, it releases the thermal energy that has been absorbed before to become gas which does not alter the temperature at all. A reduction in energy changes the arrangement of particle. There spacing between the particles also increases but not as in a gaseous state and so does the kinetic energy. The particles now are now arranged in irregular pattern.