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swat32
3 years ago
6

How many centigrams are in 0.13 oz

Chemistry
2 answers:
Paha777 [63]3 years ago
5 0

Answer:

I think the answer is 368.544 centigrams

Explanation:

I hope I helped

butalik [34]3 years ago
4 0
It is 368.5438 centigrams
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180m/173 Tl -> 180/173 Tl + ? Express your answer as a nuclear equation ​
Law Incorporation [45]

Answer: The nuclear equation is ^{180}_{173}Tl \rightarrow ^{180}_{173}Tl + ^{0}_{0}\gamma.

Explanation:

A nuclear reaction in which a heavy particle splits into another particle along with release of energy is called a nuclear fission reaction.

For example, ^{180}_{173}Tl \rightarrow ^{180}_{173}Tl + ^{0}_{0}\gamma

Here, energy is radiated in the form of gamma radiation.

Thus, we can conclude that the nuclear equation is ^{180}_{173}Tl \rightarrow ^{180}_{173}Tl + ^{0}_{0}\gamma.

4 0
2 years ago
What is the mass of 4.56 moles of copper (ii) fluoride​
musickatia [10]

Answer:

463.0 g.

Explanation:

  • We can use the following relation:

<em>n = mass/molar mass.</em>

where, n is the mass of copper(ii) fluoride​ (m = 4.56 mol),

mass of copper(ii) fluoride​ = ??? g.

molar mass of copper(ii) fluoride​ = 101.543 g/mol.

∴ mass of copper(ii) fluoride​ = (n)(molar mass) = (4.56 mol)(101.543 g/mol) = 463.0 g.

7 0
3 years ago
Calculate the concentration of CO2 in water at 25 degrees Celsius when the pressure of CO2 over the solution is 4.5 atm. At 25 d
OLEGan [10]

Answer : The concentration of CO_2 is, 0.12 M

Explanation :

Using Henry's law :

C_{CO_2}=k_H\times p_{CO_2}

where,

C_{CO_2} = concentration of CO_2 = ?

p_{CO_2} = partial pressure of CO_2 = 4.5 atm

k_H = Henry's law constant  = 3.1\times 10^{-2}mol/L.atm

Now put all the given values in the above formula, we get:

C_{CO_2}=3.1\times 10^{-2}mol/L.atm\times (4.5atm)

C_{CO_2}=0.1395M\approx 0.12M

Thus, the concentration of CO_2 is, 0.12 M

5 0
3 years ago
I am in desperate need of help will give 40 points to whoever helps me!!!!! I have a quiz tomorrow but I have no idea how to do
serious [3.7K]
All of the questions here are pertaining to the colligative properties of a solution and the preparation of solutions. Maybe, it would be best if you understand the equations to be used in order to answer these questions.<span>
Freezing point depression or Boiling point elevation:

</span><span>ΔT = -K (m) (i)

</span>ΔT is the change in the freezing point or the boiling point not the freezing point/boiling point. Therefore, it should be added to the original value of the property of the solvent. 
<span>
K is a constant called the molal freezing point depression constant and for the boiling point is the boiling point elevation constant. It is a property of the solvent. 
</span><span>
m is the concentration of the solute in the solvent in terms of molality or kg solute/kg solvent. 
</span><span>
i is the vant hoff factor which will represent the number of ions which the solute dissociates when in solution.</span>
5 0
3 years ago
The process by which particles in a solution spread out evenly is called?
padilas [110]

Answer:

this is your answer.....

7 0
3 years ago
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