<span><span>Atomic number36,</span><span>Atomic mass<span>83.80 g.mol -1,</span></span><span>Density<span>3.73 10-3 g.cm-3 at 20°C,</span></span><span>Melting point- 157 °C,</span><span>Boiling point<span>- 153° C</span></span></span>
Answer:
From the equation you will see that 1 mol of propane generates 4 mols of water.
Since the molar mass of water
M
(
H2O)=2×1+16=18g/mol
2 mol propane will generate
2
×4×18=144g of water
Explanation:
Since the molar mass of water
M
(
H2O)=2×1+16=18g/mol
2 mol propane will generate
2
×4×18=144g of water
<span>(NH4)2CO3 -> 96.09 g/mol
(6.995g ammonium carbonate)(1mol ammonium carbonate/ 96.09 g ammonium carbonate) = 0.072796 mol ammonium carbonate
In this conversion, the 'grams' unit is crossed out because it is in both the numerator and the denominator, which leaves the 'mol' unit left.
Looking at the formula (NH4)2CO3, you can look at it as if it were:
2 mol (NH4) + 1 mol (CO3) = 1 mol (NH4)2CO3
For every 1 mol of ammonium carbonate, you have 1 mol of carbonate ions and 2 moles of ammonium ions.
(0.072796 mol ammonium carbonate) = (0.072796 mol carbonate ion)+(0.363981 mol ammonium ion) </span>
