Answer: There are 576.46 number of grams present in 16.95 mol hydrogen peroxide 
.
Explanation:
Number of moles is defined as the mass of substance divided by its molar mass.
The molar mass of 
is 34.01 g/mol. Hence, mass of hydrogen peroxide present in 16.95 moles is calculated as follows.
Thus, we can conclude that there are 576.46 number of grams present in 16.95 mol hydrogen peroxide .
The Zn that is 1.33 g is used at the start of the reaction where f is 520 ml and h2 collected over water is 28oc and the atmospheric pressure is 1.0 atm.
Given If 520 ml of H2 is gathered over Wate at 28 diploma Celsius and the atmospheric strain is 1 ATM if vapour strain of wate at 28 diploma celsius is 28.three mmhg then the quantity of zn in grams taken at begin of the response is.
We recognise that
h * 2 = PT - P * h * 20 = 1atm - 0.037atm
= 0.963 atm
1 * h * 2 = Ph * 2V / R * T
= 0.963 atm x 0.520 L / 0.0821 L atm/
molK * 301
= 0.02 mol h2
= 0.02molZn
So 0.02 mol Zn x 65.39 g/mol
= 1.33 g Zn
Read more about zinc;
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Answer:
is that a question or statement?
Explanation:
Answer:
0.54 moles of N2
Explanation:
First remember to find the volume in moles, 1 mole equals 22.4 liters.
So now use the dimensional analysis to show your work.
12 liters of N2 * 1 mol /22.4 liters of N2
Now calculate this. 12 * 1/22.4 or 12/ 22.4
12/22.4 = 0.535714286.
12 has two significant digits.
With that, The answer rounds to 0.54.
So that the final answer is 0.54 moles.
Hope it helped!
