Answer:
The answer to your question is 3 ml
Explanation:
Data
Dosage = 9.0 mg/ kg
Child's weight = 42.9 pounds
Suspension = 60 mg/ml
milliliters = ?
Process
1.- Convert the weight to kg
1 pound ------------------- 0.453 kg
42.9 pounds --------------- x
x = (42.9 x 0.453) / 1
x = 19.43 kg
2.- Calculate the milligrams the child needs
1 kg of weight ------------ 9 mg
19.43 kg ---------------------- x
x = (19.43 x 9) / 1
x = 174.87 mg of oxcarbazepine
3.- Calculate the milliliters needed
60 mg of suspension ------------- 1 milliliters
174.87 mg -------------- x
x = (174.87 x 1) / 60
x = 2.9 ml ≈ 3 ml
Answer:
94.2 g/mol
Explanation:
Ideal Gases Law can useful to solve this
P . V = n . R . T
We need to make some conversions
740 Torr . 1 atm/ 760 Torr = 0.974 atm
100°C + 273 = 373K
Let's replace the values
0.974 atm . 1 L = n . 0.082 L.atm/ mol.K . 373K
n will determine the number of moles
(0.974 atm . 1 L) / (0.082 L.atm/ mol.K . 373K)
n = 0.032 moles
This amount is the weigh for 3 g of gas. How many grams does 1 mol weighs?
Molecular weight → g/mol → 3 g/0.032 moles = 94.2 g/mol
Answer:
459.126 grams of calcium chloride is needed to prepare 2.657 L of a 1.56 M solution
Explanation:
Molarity is a measure of the concentration of a solute in a solution that indicates the amount of moles of solute that appear dissolved in one liter of the mixture. In other words, molarity is the number of moles of solute that are dissolved in a given volume.
The Molarity of a solution is determined by the following expression:
Molarity is expressed in units 
In this case:
- Molarity: 1.56 M= 1.56
- Number of moles of calcium chlorine= ?
- Volume= 2.657 liters
Replacing:
Solving:
Number of moles of calcium chlorine= 1.56 M* 2.657 liters
Number of moles of calcium chlorine= 4.14 moles
In other side, you know:
- Ca: 40 g/mole
- Cl: 35.45 g/mole
Then the molar mass of the calcium chloride CaCl₂ is:
CaCl₂= 40 g/mole + 2* 35.45 g/mole= 110.9 g/mole
Now it is possible to apply the following rule of three: if in 1 mole there is 110.9 g of CaCl₂, in 4.14 moles of the compound how much mass is there?
mass= 459.126 g
<u><em>459.126 grams of calcium chloride is needed to prepare 2.657 L of a 1.56 M solution</em></u>
Answer:
Write this in a word and skeleton equation:
Solid silver chloride and an aqueous solution of nitric acid are produced when a solution of silver nitrate is reacted with a solution of hydrochloric acid.
Explanation:
Answer:
Ionic
Explanation:
Mg has 2 electron in it's outermost orbit, by donating this two electron to Sulfur it get stable mg 2+ electronic configuration while sulfur has 6 electron in it's outermost shell ,so sulfur accept this 2 electron and complete it's octet and become s2–.
