All categories

3 years ago

In the reaction H2S + NH3 NH4+ + HS–, the two Brönsted-Lowry bases are

Chemistry

2 answers:

denpristay [2]3 years ago

8 0

Answer:

Option A is correct.

The two Brönsted Lowry bases are NH₃ and HS⁻.

Explanation:

In any neutralization reaction or any reaction that seems like a neutralization reaction, the Bronsted Lowry Acid is the specie that donates a proton in reaction, the base is the specie that accepts the donated proton in the reaction.

The acid, after donating the proton becomes the conjugate base, and the base after receiving the proton becomes a specie known as the conjugate acid.

In this reaction, H₂S (acid) loses a proton to NH₃ (base) to form a HS⁻ (conjugate base) and NH₄⁺ (conjugate acid).

In a backward reaction, the conjugate acid and conjugate base form the acid and base pair respectively as required.

Hence, the two two Brönsted-Lowry bases are NH₃ and HS⁻.

Hope this Helps!!!

Usimov [2.4K]3 years ago

6 0

Answer:

A) NH3 and HS-

Explanation:

A Bronsted-Lowry base is a substance that accepts protons.

The ammonia is a Bronsted-Lowry base because can accept a proton from the hydrogen of H2S to become NH4+.

The HS⁻ is the Brønsted-Lowry base too because it has one more H atom. It has accepted a proton (H⁺), so it is a Brønsted-Lowry base.

You might be interested in

The National Environmental Policy Act was established in 1965. True or false

Mariana [72]

The answer to your question is false

5 0

3 years ago

Read 2 more answers

Lewis Diagrams- Grade 10 Chemistry<br><br> Please can someone explain this to me?

natita [175]

Lewis diagram:
well first you have to know the Valence electrons the elements which will on top of the periodic table.

for examples:
H2O
it will be O-H-O and the dots will on top. oxygen have 6 valence electrons so that mean it need 6 dots. also for H it will have 7 V-electrons.

3 0

3 years ago

What are the examples of physical chemistry?

OverLord2011 [107]

ANSWER:

Physical chemistry is the branch of chemistry that deals with the physical structure of chemical compounds, the way they react with other matter and the bonds that hold their atoms together. An example of physical chemistry is nitric acid eating through wood.

3 0

2 years ago

Janice bought 40 shares of stock at $31.82 per share. She received dividends of $1.11 per share for 1 year. (Do not use commas,

Alborosie

Answer:

$30.71 per share

Explanation:

The <em>purchase price</em> is what Janice invested for every share.

Since the stock was priced at $31.82 per share and she received a $1.11 dividend per share, her investment was:

$31.82 - $1.11 = $30.71 per share ← answer

This price is the cost for Janice, over which she shall calculate their returns (gains or losses) on the future, when she sells the shares, for instance.

The total investment of Janice was the number of shares multipled by the purchase price:

40 shares × ($31.82 - $1.11)/ share

40 shares × ($30.71) / share = $1,228.40 (total investment)

5 0

3 years ago

When methyloxirane is treated with HBr, the bromide ion attacks the less substituted position. However, when phenyloxirane is tr

konstantin123 [22]

Answer:

See explanation and picture below

Explanation:

First, in the case of methyloxirane (Also known as propilene oxide) the mechanism that is taking place there is something similar to a Sn2 mechanism. Although a Sn2 mechanism is a bimolecular substitution taking place in only step, the mechanism followed here is pretty similar after the first step.

In both cases, the H atom of the HBr goes to the oxygen in the molecule. You'll have a OH⁺ in both. However, in the case of methyloxirane the next step is a Sn2 mechanism step, the bromide ion will go to the less substitued carbon, because the methyl group is exerting a steric hindrance. Not a big one but it has a little effect there, that's why the bromide will rather go to the carbon with more hydrogens. and the final product is formed.

In the case of phenyloxirane, once the OH⁺ is formed, the next step is a Sn1 mechanism. In this case, the bond C - OH⁺ is opened on the side of the phenyl to stabilize the OH. This is because that carbon is more stable than the carbon with no phenyl. (A 3° carbon is more stable than a 2° carbon). Therefore, when this bond opens, the bromide will go there in the next step, and the final product is formed. See picture below for mechanism and products.

4 0

3 years ago