We need a work of 294210 watts to pump the water over the top. 
<h3>Work needed to pump all the water over the top</h3>
Since the <em>cross section</em> area of the trough (
), in square meters, varies with the height of the water (
), in meters, and considering that <em>pumping</em> system extracts water at <em>constant</em> rate, then the work needed to pump all the water (
), in joules, is:
(1)
Where:
- Pressure of the infinitesimal volume, in pascals.
- Volume, in cubic meters. 
- Maximum volume allowed by the trough, in cubic meters.
The <em>infinitesimal</em> volume is equivalent to the following expression:
(2)
Since the area is directly proportional to the height of the water, we have the following expression:
(3)
Where:
- Area of the base of the trough, in square meters.
- Maximum height of the water, in meters.
In addition, we know that pressure of the water is entirely hydrostatic:
(4)
Where:
- Density of water, in kilograms per cubic meters.
- Gravitational acceleration, in meters per square second.
By (2), (3) and (4) in (1):
(5)
Where:
- Width of the base of the triangle, in meters.
- Length of the base of the triangle, in meters. - - Maximum height of the triangle, in meters.
The resulting expression is:
(5b)
If we know that 
, 
, 
, 
and 
, then the work needed to pump the water is:
We need a work of 294210 watts to pump the water over the top.
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