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butalik [34]
3 years ago
12

A radio station broadcasts at a frequency of 590,000 Hz. What is the wavelength of the radio waves?​

Chemistry
1 answer:
34kurt3 years ago
8 0

Answer:

f = frequency = 590,000 Hz ===> 59×10^4 Hz

λ = Wavelength = ?

c = Speed of light in a vacuum = 3 × 10^8 m/s

** Hz = 1/sec

___o___o___

f =  \frac{c}{λ}  \\  \\ λ =  \frac{c}{f}  \\  \\ λ =  \frac{3 \times  {10}^{8} }{590000}  \\  \\ λ =  \frac{3 \times  {10}^{8} }{59 \times  {10}^{4} }  \\  \\ λ =0.0508  \times  {10}^{4}  \: m \\  \\ λ = 508 \times  {10}^{ - 4}  \times  {10}^{4}  \: m \\  \\ λ = 508  \: m

I hope I helped you^_^

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Answer:

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7 0
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For Questions 1 through 4 - Consider a solution prepared by combining 45.0 g of BaCl2 with enough water to prepare a 750.0 mL of
astra-53 [7]

<u>Answer:</u> The molality of barium chloride solution is 0.289 m

<u>Explanation:</u>

To calculate the mass of water, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of water = 1 g/mL

Volume of water = 748 mL

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{748mL}\\\\\text{Mass of water}=(1g/mL\times 748mL)=748g

To calculate the molality of solution, we use the equation:

\text{Molality}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

m_{solute} = Given mass of solute (barium chloride) = 45.0 g

M_{solute} = Molar mass of solute (barium chloride) = 208.23  g/mol

W_{solvent} = Mass of solvent (water) = 748 g

Putting values in above equation, we get:

\text{Molality of barium chloride solution}=\frac{45\times 1000}{208.23\times 748}\\\\\text{Molality of barium chloride solution}=0.289m

Hence, the molality of barium chloride solution is 0.289 m

5 0
3 years ago
What are the isotopes? how all of the isotopes of an atom are similar and how are they different?
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5 0
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Give the correct nuclide symbol for gallium-71. How many protons and neutrons are in this isotope?
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3 years ago
2 UO2+ + 4 H+U4+ + UO22+ + 2 H2O is second order in UO2+ and third order overall. Complete the rate law for this reaction in the
mr Goodwill [35]

Answer:

r=k[UO_2^+]^2[H^+]

Explanation:

The given reaction is :-

2UO_2^++4H^+\rightarrow U^{4+}+UO_2^{2+}+2H_2O

According to the law of mass action:-

The rate of the reaction is directly proportional to the active concentration of the reactant which each are raised to the experimentally determined coefficients which are known as orders. The rate is determined by the slowest step in the reaction mechanics.

Order of in the mass action law is the coefficient which is raised to the active concentration of the reactants. It is experimentally determined and can be zero, positive negative or fractional.

The order of the whole reaction is the sum of the order of each reactant which is raised to its power in the rate law.  

m = 2 =  is order with respect to UO_2^+

n = order with respect to H+

overall order = m+n = 3

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Rate law is:-

r=k[UO_2^+]^2[H^+]

6 0
3 years ago
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