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3 years ago

What are the isotopes? how all of the isotopes of an atom are similar and how are they different?

1 answer:

5 0

Isotopes are the same element with a different mass number. They are similar because once again the protons are equal to the atomic number which keeps the identity of the atom the same. But they are different because the masses of each is different.

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An atom containing 25 protons, 30 neutrons and 25 electrons will have an atomic mass of:

aliya0001 [1]

Atomic mass=no of neutron+no of electron
Atomic mass=25+30
Atomic mass=55

8 0

3 years ago

How many branches of chemistry are there .

faltersainse [42]

Answer:

Explanation:

Analytical chemistry

Organic chemistry

Inorganic chemistry

physical chemistry

Biochemistry

6 0

3 years ago

Read 2 more answers

What is the solubility product expression for Ag2CO3

Dominik [7]

<span> Ksp = [Ag+]^2[CO32-]that should be it </span>

7 0

3 years ago

3. 2KOH + H2SO4 = K2SO4 + 2H2O what chemical reaction is it.

Serjik [45]

From what is given, double replacement is what it is

5 0

2 years ago

Assume the hydrolysis of ATP proceeds with ΔG′° = –30 kJ/mol. ATP + H2O → ADP + Pi Which expression gives the ratio of ADP to AT

Andru [333]

Answer:

$6.14\cdot 10^{-6}$

Explanation:

Firstly, write the expression for the equilibrium constant of this reaction:

$K_{eq} = \frac{[ADP][Pi]}{ATP}$

Secondly, we may relate the change in Gibbs free energy to the equilibrium constant using the equation below:

$\Delta G^o = -RT ln K_{eq}$

From here, rearrange the equation to solve for K:

$K_{eq} = e^{-\frac{\Delta G^o}{RT}}$

Now we know from the initial equation that:

$K_{eq} = \frac{[ADP][Pi]}{ATP}$

Let's express the ratio of ADP to ATP:

$\frac{[ADP]}{[ATP]} = \frac{[Pi]}{K_{eq}}$

Substitute the expression for K:

$\frac{[ADP]}{[ATP]} = \frac{[Pi]}{K_{eq}} = \frac{[Pi]}{e^{-\frac{\Delta G^o}{RT}}}$

Now we may use the values given to solve:

$\frac{[ADP]}{[ATP]} = \frac{[Pi]}{K_{eq}} = \frac{[Pi]}{e^{-\frac{\Delta G^o}{RT}}} = [Pi]e^{\frac{\Delta G^o}{RT}} = 1.0 M\cdot e^{\frac{-30 kJ/mol}{2.5 kJ/mol}} = 6.14\cdot 10^{-6}$

7 0

4 years ago