Explanation:
Let's solve the problem by using conservation of momentum:
m1 u1 + m2 u2 = m1 v1 + m2 v2
where:
m1 = 3.5 g is the mass of the blue marble
m2= 1.2 g is the mass of the red marble
u1 = 15 cm/s is the initial velocity of the blue marble
u2 = 3.5 cm/s is the initial velocity of the red marble
v1 = 5.5 cm/s is the final velocity of the blue marble
We can find the final velocity of the red marble by re-arranging the equation and solving for v2 :
v2 = 1/m²(m1 u1 + m2 u2 - m1 v1)=
=1/1.2(3.5×15+1.2×3.5−3.5×5.5 )=31cm/s
Answer:
C) Pnew=Poriginal/9
Explanation:
From the given conditions:
Original area, 
New area of the barrel bottom panel after increasing by a factor of 3:
On increasing the radius the area now becomes:
As we know that there will be no increase in the down-force since the height remains constant.
Pressure is given as:
∴New pressure:
The resultant force is 5N.So the box moves to right with constant acceleration.
Answer:
Consider the following calculations
Explanation:
a ) velocity of the glass is v = distance / time
= 5 X 10-3 / 7 X 365.24 X 24 X 60 X 60
v = 2.263 X 10-11 m/sec
the speed of the light in vaccum is C
C = 3 X 108 m/sec
n = C / v
n = 3 X 108 / 2.263 X 10-11
n = 1.32567 X 1019
b ) given is 40 km/hr
= 40 X 103 / 60 X 60
= 11.11 m/sec
n = C / v
n = 3 X 108 / 11.11
n = 27002700.27
