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fiasKO [112]
3 years ago
15

A large blue marble of mass 3.5 g is moving to the right with a velocity of 15 cm/s. The large marble hits a small red marble of

mass 1.2 g that is moving to the right with a velocity of 3.5 cm/s. After the collision, the blue marble moves to the right with a velocity of 5,5 cm/s.​
Physics
1 answer:
Aneli [31]3 years ago
7 0

Explanation:

Let's solve the problem by using conservation of momentum:

m1 u1 + m2 u2 = m1 v1 + m2 v2

where:

m1 = 3.5 g  is the mass of the blue marble

m2= 1.2 g is the mass of the red marble

u1 = 15 cm/s  is the initial velocity of the blue marble

u2 = 3.5 cm/s is the initial velocity of the red marble

v1 = 5.5 cm/s is the final velocity of the blue marble

We can find the final velocity of the red marble by re-arranging the equation and solving for v2 :

v2 = 1/m²(m1 u1 + m2 u2 - m1 v1)=

=1/1.2(3.5×15+1.2×3.5−3.5×5.5 )=31cm/s

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Explanation:

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Then P(x\geq a)=0.72

The critical value corresponds to p-value 0.72 :z=0.5828415

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6 0
3 years ago
A mass of 5 kg is moving at 5 m/s when it collides with another mass of 2 kg moving in the same direction at 2 m/s. After the co
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Answer:

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