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fiasKO [112]
4 years ago
15

A large blue marble of mass 3.5 g is moving to the right with a velocity of 15 cm/s. The large marble hits a small red marble of

mass 1.2 g that is moving to the right with a velocity of 3.5 cm/s. After the collision, the blue marble moves to the right with a velocity of 5,5 cm/s.​
Physics
1 answer:
Aneli [31]4 years ago
7 0

Explanation:

Let's solve the problem by using conservation of momentum:

m1 u1 + m2 u2 = m1 v1 + m2 v2

where:

m1 = 3.5 g  is the mass of the blue marble

m2= 1.2 g is the mass of the red marble

u1 = 15 cm/s  is the initial velocity of the blue marble

u2 = 3.5 cm/s is the initial velocity of the red marble

v1 = 5.5 cm/s is the final velocity of the blue marble

We can find the final velocity of the red marble by re-arranging the equation and solving for v2 :

v2 = 1/m²(m1 u1 + m2 u2 - m1 v1)=

=1/1.2(3.5×15+1.2×3.5−3.5×5.5 )=31cm/s

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4 0
2 years ago
The coordinate of a particle in meters is given by x(t)=1 6t- 3.0t , where the time tis in seconds. The
Reika [66]

Complete question:

The coordinate of a particle in meters is given by x(t)=1 6t- 3.0t³ , where the time tis in seconds. The

particle is momentarily at rest at t is:

Select one:

a. 9.3s

b. 1.3s

C. 0.75s

d.5.3s

e. 7.3s

​

Answer:

b. 1.3 s

Explanation:

Given;

position of the particle, x(t)=1 6t- 3.0t³

when the particle is at rest, the velocity is zero.

velocity = dx/dt

dx /dt = 16 - 9t²

16 - 9t² = 0

9t² = 16

t² = 16 /9

t = √(16 / 9)

t = 4/3

t = 1.3 s

Therefore, the particle is momentarily at rest at t = 1.3 s

6 0
3 years ago
describe the following wave characteristics associated with Transverse and longitudinal waves-amplitude, wavelength, and frequen
sasho [114]

frequency is how many times a sec the thing vibrates

amp is the size of the vibration

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8 0
3 years ago
A dog is walking back home and its motion is modeled by the graph above. What position was the dog at 3 seconds after it started
hammer [34]
6 meters because 6/3 = 10/5
4 0
3 years ago
A 0.80 kg basketball traveling upward at 5.0 m/s impacts an 8.0 10 kg tennis ball traveling downward at 5.0 m/s. The basketball’
vlabodo [156]

To solve this problem we will apply the concepts related to the conservation of momentum. This can be defined as the product between the mass and the velocity of each object, and by conservation it will be understood that the amount of the initial momentum is equal to the amount of the final momentum. By the law of conservation of momentum,

m_1u_1+m_2u_2 = m_1v_1+m_2v_2

Here,

m_1 = Mass of Basketball

m_2 = Mass of Tennis ball

u_1 = Initial velocity of Basketball

u_2 = Initial Velocity of Tennis ball

v_1 = Final velocity of Basketball

v_2 = Final velocity of the tennis ball

Replacing,

(0.8)(0.5)+(0.1)(-5.0)=(0.8)(0.3)+(0.1)v_2

Solving for the final velocity of the tennis ball

v_2 = 11m/s^2

Therefore the velocity of the tennis ball after collision is 11 m/s

3 0
3 years ago
Read 2 more answers
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