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OverLord2011 [107]
3 years ago
11

How to solve question #2?

Physics
1 answer:
Vera_Pavlovna [14]3 years ago
5 0
2a for example the first one,2sec. You know that every second it moves 3metres further. So 2x3=6 but you start at 0.50m so 6+0.50=6.5
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Read 2 more answers
What is the frequency of the fundamental mode of vibration of a steel piano wire stretched to a tension of 440 N? The wire is 0.
algol [13]

Answer:

<h2><em>220.698Hz</em></h2>

Explanation:

The fundamental frequency f₀ is expressed as f₀ =V/2L where;

V is the speed of the string = \sqrt{\frac{T}{M} }

m is the mass of the string

L is the length of the string

T is the tension in the string

f₀ = \frac{1}{2L} \sqrt{\frac{T}{m} }

Given datas

m = 5.69g = 0.00569 kg

T = 440N

L = 0.630 m

Required

Fundamental frequency of the steel piano wire f₀

f_0 = \frac{1}{2(0.630)}\sqrt{\frac{440}{0.00569} } \\ \\f_0 =  \frac{1}{1.26}\sqrt{77,328.65 } \\\\f_0 = \frac{1}{1.26} * 278.08\\\\f_0 = 220.698Hz

<em>Hence the frequency of the fundamental mode of vibration of the steel piano wire stretched to a tension of 440N is 220.698Hz</em>

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3 years ago
PLZ HELP ILL GIVE RBAINLIEST
Rom4ik [11]
All of the above .........
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