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3 years ago

Solve using the square root method X2=25

Mathematics

2 answers:

aleksandrvk [35]3 years ago

8 0

Answer:

Square root =

remember :

$\boxed {x^2 = \pm a}$

x² = ± a

x = √±a

x = √±25

x = ±5

• x = 5 and -5

geniusboy [140]3 years ago

3 0

X^2=25
sqrt x^2= sqrt 25
x=5

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A grasshopper jumps off a tree stump. The height, in feet, of the grasshopper above the ground after t seconds is modeled by the

klasskru [66]

Answer:

Hence, Grasshopper will land on the ground after 1.5 sec.

Step-by-step explanation:

It s given that:

The height, in feet, of the grasshopper above the ground after t seconds is modeled by the function:

$h(t)=-t^2+\dfrac{4}{3}t+\dfrac{1}{4}$

Now we are asked to find:

In how many seconds will the grasshopper land on the ground?

i.e. we have to find the value of t such that h(t)=0

i.e.

$-t^2+\dfrac{4}{3}t+\dfrac{1}{4}=0$

i.e. we need to find the roots of the given quadratic equation.

On solving the quadratic equation or plotting it's graph we could observe that the point where h(t)=0 are:

$t=-\dfrac{1}{6},t=\dfrac{3}{2}$

As time can't be negative hence we will consider:

$t=\dfrac{3}{2}=1.5sec$

Hence, grasshopper will land on the ground after 1.5 sec.

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3 years ago

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Harlamova29_29 [7]

Answer:

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3 years ago

Suppose that in a random selection of 100 colored candies, 28% of them are blue. The candy company claims that the percentage

Zigmanuir [339]

Answer:

We conclude that the percentage of blue candies is equal to 29%.

Step-by-step explanation:

We are given that in a random selection of 100 colored candies, 28% of them are blue. The candy company claims that the percentage of blue candies is equal to 29%.

Let p = population percentage of blue candies

So, Null Hypothesis, $H_0$ : p = 29% {means that the percentage of blue candies is equal to 29%}

Alternate Hypothesis, $H_A$ : p $\neq$ 29% {means that the percentage of blue candies is different from 29%}

The test statistics that will be used here is One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of blue coloured candies = 28%

n = sample of colored candies = 100

So, the test statistics = $\frac{0.28-0.29}{\sqrt{\frac{0.29(1-0.29)}{100} } }$

= -0.22

The value of the z-test statistics is -0.22.

Also, the P-value of the test statistics is given by;

P-value = P(Z < -0.22) = 1 - P(Z $\leq$ 0.22)

= 1 - 0.5871 = 0.4129

Now, at a 0.10 level of significance, the z table gives a critical value of -1.645 and 1.645 for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of z, so we insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that the percentage of blue candies is equal to 29%.

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3 years ago

Combine the like terms to create an equivalent expression -k - ( - 8k)

Svetllana [295]

____________________________________________________

Answer:

____________________________________________________

Step-by-step explanation:

We are trying to combine like terms with the expression: -k - ( - 8k)

We are pretty much solving it.

Solve:

-k - ( - 8k)

The "- ( -" turns into a plus sign.

So it would look like:

-k - -8k or -k + 8k

Now, you would finish solving

-k + 8k = 7k

____________________________________________________

3 0

3 years ago

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Solve using the square root method X2=25​

Solve using the square root method X2=25