Answer:
x = 3
Step-by-step explanation:
5(x+1) = 20
x+1 = 20/5
or, x+1 = 4
or, x = 4-1
so, x = 3
The given inequality holds for the open interval (2.97,3.03)
It is given that
f(x)=6x+7
cL=25
c=3
ε=0.18
We have,
|f(x)−L| = |6x+7−25|
= |6x−18|
= |6(x−3)|
= 6|x−3|
Now,
6|x−3| <0.18 then |x−3|<0.03 ----->−0.03<x-3<0.03---->2.97<x<3.03
the given inequality holds for the open interval (2.97,3.03)
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Although part of your question is missing, you might be referring to this full question: For the given function f(x) and values of L,c, and ϵ0, find the largest open interval about c on which the inequality |f(x)−L|<ϵ holds. Then determine the largest value for δ>0 such that 0<|x−c|<δ→|f(x)−|<ϵ.
f(x)=6x+7,L=25,c=3,ϵ=0.18
.
Substitute 4 for m and 6 for n
Y= 4(3+2(6))
Y= 4(3+12)
Y=4(15)
Y=60
The perimeter is 16 inches
4.5+5.5+6=16
what kind od sandwich cost 12.36 and why would you leave a tip if it cost so much
also just add 12.36 plus 1.84
