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Minchanka [31]
3 years ago
14

Pls help quickly i will mark u brainliest

Mathematics
1 answer:
Bezzdna [24]3 years ago
5 0

Answer:

What u need help on

Step-by-step explanation:

Nothing is here hello.

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hi can someone please help me I think the answer is b, but I think I am wrong. will give brainliest ​
Leviafan [203]

Answer:

b

Step-by-step explanation:

7 0
3 years ago
Solve the equation 18y - 17 = 7 for y
miv72 [106K]

Answer:

y = 1.3

Step-by-step explanation:

18y - 17 = 7

18y = 7 + 17

18y = 24

y = 24/18

y = 1.3

hope it helps!

8 0
3 years ago
Read 2 more answers
W−2+2w=6+5w please helppp
Lerok [7]

Answer:

Step-by-step explanation:

Simplifying

W + -2 + 2w = 6 + 5w

Reorder the terms:

-2 + W + 2w = 6 + 5w

Solving

-2 + W + 2w = 6 + 5w

Solving for variable 'W'.

Move all terms containing W to the left, all other terms to the right.

Add '2' to each side of the equation.

-2 + W + 2 + 2w = 6 + 2 + 5w

Reorder the terms:

-2 + 2 + W + 2w = 6 + 2 + 5w

Combine like terms: -2 + 2 = 0

0 + W + 2w = 6 + 2 + 5w

W + 2w = 6 + 2 + 5w

Combine like terms: 6 + 2 = 8

W + 2w = 8 + 5w

Add '-2w' to each side of the equation.

W + 2w + -2w = 8 + 5w + -2w

Combine like terms: 2w + -2w = 0

W + 0 = 8 + 5w + -2w

W = 8 + 5w + -2w

Combine like terms: 5w + -2w = 3w

W = 8 + 3w

Simplifying

W = 8 + 3w

6 0
3 years ago
Read 2 more answers
Evaluate the integral by reversing the order of integration. Integral from 0 to 1 integral from √x to 1 of 5/(y³+1) dydx
ELEN [110]

Answer:

⁵/₃ ln 2

Step-by-step explanation:

∫₀¹ ∫√ₓ¹ 5 / (y³ + 1) dy dx

We want to change the order of integration.  To do this, we start by graphing the region contained by the four limits.

x = 0, x = 1

y = √x, y = 1

(Notice that y = √x is the same as x = y²).

Once we've graphed the region, we need to write the domain of x in terms of y.  In this case, 0 < x < y².

Then, we find the range: 0 < y < 1.

Now we can rewrite the integral:

∫₀¹ ∫₀ʸ² 5 / (y³ + 1) dx dy

Notice that the integrand itself, 5 / (y³ + 1), does not change.  Only the limits have changed.

Solve the integral.

∫₀¹ [ 5 / (y³ + 1) x |₀ʸ² ] dy

∫₀¹ [ 5y² / (y³ + 1) ] dy

⁵/₃ ∫₀¹ [ 3y² / (y³ + 1) ] dy

(⁵/₃ ln|y³ + 1|) |₀¹

⁵/₃ ln|1³ + 1| − ⁵/₃ ln|0³ + 1|

⁵/₃ ln 2

7 0
3 years ago
Please help thank you all
nalin [4]
400 liters ........ hope this helps
6 0
3 years ago
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