You want to isolate b, so start by multiplying the whole equation by three to get rid of it in the denominator:
(v=1/3 bh)3
3v=bh
Then to isolate b divide the whole equation by h:
(3v=bh)/h
3v/h=b
These are the steps:
1. Find area of the two triangles.
2. Find area of the rectangle.
3. Add them up.
<u>Step 1: Find area of the two triangles:</u>
Formula : Area of triangle = 1/2 x base x height
Both triangles are identical.
Height = 5m
Base = 6 + 6 + 12 = 24
Area = 1/2 x 24 x 5 = 60 m²
<u>Step 2: Find the area of the rectangle:</u>
Formula : Area = Length x Width
Area = 12 x 7 = 84 m²
<u>Step 3: Find the total area:</u>
60 + 84 = 144 m²
Answer: 144 m²
do them how becuase I have be no idea
I would say c but that is just a guess
P(t) = P₀ e^(kt)
<span>Where P₀ is the initial population, </span>
<span>P(t) is the population after "t" time. </span>
<span>t is your rate (can be hours, days, years, etc. in this case, hours) </span>
<span>k is the growth constant for this particular problem. </span>
<span>So using the information given, solve for k: </span>
<span>P₀ = 2000 </span>
<span>P(4) = 2600 </span>
<span>P(t) = P₀ e^(kt) </span>
<span>2600 = 2000e^(k * 4) </span>
<span>1.3 = e^(4k) </span>
<span>Natural log of both sides: </span>
<span>ln(1.3) = 4k </span>
<span>k = ln(1.3) / 4 </span>
<span>Now that we have a value for "k", use that, the same P₀, then solve for P(17): </span>
<span>P(t) = P₀ e^(kt) </span>
<span>P(17) = 2000 e^(17ln(1.3) / 4) </span>
<span>Using a calculator to get ln(1.3) then to simplify from there, we get: </span>
<span>P(17) ≈ 2000 e^(17 * 0.262364 / 4) </span>
<span>P(17) ≈ 2000 e^(4.460188 / 4) </span>
<span>P(17) ≈ 2000 e^(1.115047) </span>
<span>P(17) ≈ 2000 * 3.0497 </span>
<span>P(17) ≈ 6099.4 </span>
<span>Rounded to the nearest unit: </span>
<span>P(17) ≈ 6099 bacteria hope i could help =)))</span>
