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maxonik [38]
2 years ago
9

Express 5940 as the product of prime factors.​

Mathematics
2 answers:
vladimir1956 [14]2 years ago
6 0

Answer:

5940= 2 x 2 x 3 x 3 x 3 x 5 x  11

Step-by-step explanation:

valentina_108 [34]2 years ago
5 0

Step-by-step explanation:

5940 = 2×2×3×3×3×5×11

HOPE IT HELPS YA

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1/3(b+4)= 1/2<br> What is the value of b?
Leni [432]

Answer:

A is 1 and b is 12

Step-by-step explanation:

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3 years ago
Let omega be a complex number such that omega^3 = 1. Find all possible values of {1}{1 + \omega} + {1}{1 + \omega^2}. Enter all
Norma-Jean [14]

Answer:

1 is Answer.

Step-by-step explanation

\frac{1}{1+omega^{2} } + \frac{1}{1+omega }\\

= \frac{(-1)*(omega + 1)}{omega^{2}  }

As we know that ω²+ω+1=0

Thus putting in above equation, we get

= \frac{1}{(-1)*omega } + \frac{1}{(-1)*omega^{2}  }

Rearranging and simplifying:

= \frac{-1}{omega } + \frac{-1}{omega^{2}  }

= \frac{(-1)*(omega + 1)}{omega^{2}  }

= \frac{(-1)*(- omega^{2} )}{omega^{2}  }

= 1 Answer

8 0
3 years ago
Given the following triangle, if b = 9 and B = 15°, find a.<br><br> 0.27<br> 2.41<br> 33.59
SVEN [57.7K]
SOH,CAH, TOA so it would be TANGENT since it would be Opposite over Adjacent. Tan(15) = 9/a put Tan(15) onto your calculator it would be .267949 round that to .27 = 9/a cross multiply  
a = 33.588. C is the correct answer.
7 0
3 years ago
Read 2 more answers
What is the value of x?
frez [133]

\left\{\begin{array}{ccc}x+2y=4&\text{multiply both sides by 5}\\4x-5y=42&\text{multiply both sides by 2}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}5x+10y=20\\8x-10y=84\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad13x=104\qquad\text{divide both sides by 13}\\\\\boxed{x=8}\\\\Answer:\ \boxed{\boxed{x=8}}

5 0
3 years ago
Please help ASAP!
Kruka [31]

First, recall that

\sin(-\theta)=-\sin\theta

So if \sin(-\theta)=\dfrac15, then \sin\theta=-\dfrac15.

Second,

\tan\theta=\dfrac{\sin\theta}{\cos\theta}

We know that \tan\theta>0 and \sin\theta, which means we should also have \cos\theta.

Third,

\sin^2\theta+\cos^2\theta=1\implies\cos\theta=\pm\sqrt{1-\sin^2\theta}

but as we've already shown, we need to have \cos\theta, so we pick the negative root.

Finally,

\tan\theta=\dfrac{\sin\theta}{\cos\theta}\iff\dfrac6{\sqrt{12}}=\dfrac{-\frac15}{\cos\theta}\implies\cos\theta=-\dfrac1{5\sqrt3}

Unfortunately, none of the given answers match, so perhaps I've misunderstood one of the given conditions... In any case, this answer should tell you everything you need to know to find the right solution from the given options.

6 0
3 years ago
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