59 = j + 29
59-29=j+29-29
30 = j
(or you could rewrite it as j=30)
hope this helps!! :)
There's an infinite number of ways we can rewrite 16 3/4, some of them being:
16 3/4
16 6/8
16 12/16
16 24/32
16.75
67/4
335/20
670/40
etc.
I hope it will help you ;)
Given: The given function is
To find: Here we need to find the value of c for which f(x,y) will be a joint
discrete probability density function.
Solution:
Now, to find c we have,
![\int\limits^3_{-2} \,\int\limits^2_0 {f(x,y)} \, dx dy\\=\int\limits^3_{-2} \,\int\limits^2_0 {c(x-y)} \, dx dy\\\\=\int\limits^3_{-2} \,[2c-2cy]dy\\=10c-5c\\=5c\\The integral should be1.\\So, 5c=1\\](https://tex.z-dn.net/?f=%5Cint%5Climits%5E3_%7B-2%7D%20%5C%2C%5Cint%5Climits%5E2_0%20%7Bf%28x%2Cy%29%7D%20%5C%2C%20dx%20dy%5C%5C%3D%5Cint%5Climits%5E3_%7B-2%7D%20%5C%2C%5Cint%5Climits%5E2_0%20%7Bc%28x-y%29%7D%20%5C%2C%20dx%20dy%5C%5C%5C%5C%3D%5Cint%5Climits%5E3_%7B-2%7D%20%5C%2C%5B2c-2cy%5Ddy%5C%5C%3D10c-5c%5C%5C%3D5c%5C%5CThe%20integral%20should%20be1.%5C%5CSo%2C%205c%3D1%5C%5C)
∴
Therefore, the required value of c is 1/5.
Answer:
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