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2 years ago

Raj is 3 inches taller than Howared. Let h represent Howards height. write an algebraic expression to represent Raj's height.

1 answer:

4 0

Answer:
Let's say Raj's height is 60 inches
60-3 = H
H= Howard's height
60 = Raj's height
Or it could be with two variables
R-3 = H
R = Raj's height

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I need help on this one I have the image attached

mart [117]

Answer:

x = 40

Step-by-step explanation:

The ADF is 90 degrees so the CAF will also be 90

So you do

( x + 15 ) + 90 + 35 = 180

x + 15 + 90 + 35 - 90 = 180 -90

x + 15 + 35 = 90

x + 15 + 35 - 35 = 90 - 35

x + 15 = 55

x + 15 - 15 = 55 - 15

x = 40

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3 years ago

stealth61 [152]

Answer:

8589465 pages are unread

Step-by-step explanation:

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3 years ago

Read 2 more answers

If a student was randomly guessing while completing a 20 question multiple choice exam, what is the probability they would score

mario62 [17]

Answer:

you want 4 correct and 16 incorrect

there are 20 questions

each question has four answers, so

P(right answer) = 1/4

P(wrong answer) = 3/4

----

Since you want 4 correct of 20 we have a combination of 20C4

This is a binomial problem where p = 1/4, q = 3/4 and we get

(20 "choose" 4)*(probability correct)^(number correct)*(probability incorrect)^(number incorrect)

putting numbers in we get

(20c4)*(1/4)^4*(3/4)^16

This gives us

~ .189685

Step-by-step explanation:

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4 years ago

The product of -16 and an unknown number equals -256. What is the value of the unknown number?

nikitadnepr [17]

16 is the unknown value.

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3 years ago

A solid is formed by adjoining two hemispheres to the ends of a right circular cylinder. An industrial tank of this shape must h

mestny [16]

Answer:

Radius =6.518 feet

Height = 26.074 feet

Step-by-step explanation:

The Volume of the Solid formed = Volume of the two Hemisphere + Volume of the Cylinder

Volume of a Hemisphere $=\frac{2}{3}\pi r^3$

Volume of a Cylinder $=\pi r^2 h$

Therefore:

The Volume of the Solid formed

$=2(\frac{2}{3}\pi r^3)+\pi r^2 h\\\frac{4}{3}\pi r^3+\pi r^2 h=4640\\\pi r^2(\frac{4r}{3}+ h)=4640\\\frac{4r}{3}+ h =\frac{4640}{\pi r^2} \\h=\frac{4640}{\pi r^2}-\frac{4r}{3}$

Area of the Hemisphere = $2\pi r^2$

Curved Surface Area of the Cylinder = $2\pi rh$

Total Surface Area=

$2\pi r^2+2\pi r^2+2\pi rh\\=4\pi r^2+2\pi rh$

Cost of the Hemispherical Ends = 2 X Cost of the surface area of the sides.

Therefore total Cost, C

$=2(4\pi r^2)+2\pi rh\\C=8\pi r^2+2\pi rh$

Recall: $h=\frac{4640}{\pi r^2}-\frac{4r}{3}$

Therefore:

$C=8\pi r^2+2\pi r(\frac{4640}{\pi r^2}-\frac{4r}{3})\\C=8\pi r^2+\frac{9280}{r}-\frac{8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{24\pi r^2-8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{16\pi r^2}{3}\\C=\frac{27840+16\pi r^3}{3r}$