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Nastasia [14]
2 years ago
9

Answer ASAP please this is important

Mathematics
1 answer:
saul85 [17]2 years ago
8 0

Answer:

  1. 7 students like art only.
  2. 32 students
  3. 18 students
  4. 4 students
  5. 9 students
  6. x squared - 2
  7. 7x-10
  8. x times 10
  9. 3+ 2x
  10. 2x - (2x squared)
  11. 4+-4=0
  12. 6+6=12
  13. (2 times -2 times 3) squared = -144
  14. 0-5= -5

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In the square ABCD, AE = 3x + 5 and BD = 10x + 2. What is the length of line AC?
zubka84 [21]
BD = 2 AE
10 x + 2 = 2 * ( 3 x + 5 )
10 x + 2 = 6 x + 10
10 x - 6 x = 10 - 2
4 x = 8
x = 8 : 4
x = 2
And the line AC is equal to BD.
AC = 10 * 2 + 2 = 20 + 2 = 22
Answer:
3.  22
6 0
3 years ago
Your car can drive 300 miles on a tank of 15 gallons. How far can it drive on 40<br> gallons?
Flura [38]

Answer:

800

Step-by-step explanation:

since 300 divided by 15 is 20.

20 x 40= 800

3 0
3 years ago
Read 2 more answers
Find the edge length of the cube
const2013 [10]

Answer:

5

Step-by-step explanation:

follow me if I'm right

6 0
3 years ago
A rectangular field with one side along a river is to be fenced. Suppose that no fence is needed along the river, the fence on t
Andreas93 [3]

Answer:

a) Side Parallel to the river: 200 ft

b) Each of the other sides: 400 ft

Step-by-step explanation:

Let L represent side parallel to the river and W represent width of fence.

The required fencing (F) would be F=L+2W.

We have been given that field must contain 80,000 square feet. This means area of field must be equal to 80,000.

LW=80,000...(1)

We are told that the fence on the side opposite the river costs $20 per foot, and the fence on the other sides costs $5 per foot, so total cost (C) of fencing would be C=20L+5(2W)\Rightarrow 20L+10W.

From equation (1), we will get:

L=\frac{80,000}{W}

Upon substituting this value in cost equation, we will get:

C=20(\frac{80,000}{W})+10W

C=\frac{1600,000}{W}+10W

C=1600,000W^{-1}+10W

To minimize the cost, we need to find critical points of the the derivative of cost function as:

C'=-1600,000W^{-2}+10

-1600,000W^{-2}+10=0

-1600,000W^{-2}=-10

-\frac{1600,000}{W^2}=-10

-10W^2=-1,600,000

W^2=160,000

\sqrt{W^2}=\pm\sqrt{160,000}  

W=\pm 400

Since width cannot be negative, therefore, the width of the fencing would be 400 feet.

Now, we will find the 2nd derivative as:

C''=-2(-1600,000)W^{-3}

C''=3200,000W^{-3}

C''=\frac{3200,000}{W^3}

Now, we will substitute W=400 in 2nd derivative as:

C''(400)=\frac{3200,000}{400^3}=\frac{3200,000}{64000000}=0.05

Since 2nd derivative is positive at W=400, therefore, width of 400 ft of the fencing will minimize the cost.

Upon substituting W=400 in L=\frac{80,000}{W}, we will get:

L=\frac{80,000}{400}\\\\L=200

Therefore, the side parallel to the river will be 200 feet.

4 0
3 years ago
Estimate. then find the sum. 1.20 plus 0.34
Trava [24]
1.20 + 0.34 = 1.54
That is the answer.
5 0
3 years ago
Read 2 more answers
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