Answer:
2 * 10 ^-4
Step-by-step explanation:
We need the first number to be between 1 and less than 10
.0002
2 * 10 ^ exponent
We move the decimal 4 places to the right. Since we move it to the right the exponent is negative and is the number of places we moved the decimal
2 * 10 ^-4
If X is between P and Q, then PQ is the whole line segment and XQ and XP are line segments that add up to PQ. Therefore, you can make an equation where XQ and XP add up to PQ.
XQ + XP = PQ
(3k) + (7k - 2) = 6k + 18
Combine like terms.
10k - 2 = 6k + 18
Add 2 to both sides.
10k = 6k + 20
Subtract 6k from both sides.
4k = 20
Divide both sides by 4.
k = 5
Plug 5 for k into XP.
XP = 7(5) - 2 ⇒ 35 - 2
XP = 33
Wait let me know that the .12 means in the first question and i will fix the answer
int (x)(cosx) dx
u=x ----> take derivative du=dx
dv=cosx -----> take integral v=sinx
now use integration by parts
u v - int (v)du
x sinx - int (sinx) (1) dx=
x sinx - (-cos(x)) + c =
answer is = x sinx + cosx + c
49x^2 = 36
take square roots of both sides:-
7x = +/- 6
x = 6/7, -6/7.
That's really hard I can't figure it out at all by any chance
